Question

If the frequency of the disorder in the population is 0.000081, what is the percentage of heterozygous carriers?

Answer 1

The frequency of the disorder in the population is 0.000081, So, the percentage of heterozygous carriers would be 0.018.

Unlike homozygous, being heterozygous means you have two different alleles. You inherited a different version from each parent. In a heterozygous genotype, the dominant allele overrules the recessive one. Therefore, the dominant trait will be expressed. The recessive trait won't show, but you're still a carrier.

The presence of two different alleles at a particular gene locus. A heterozygous genotype may include one normal allele and one mutated allele or two different mutated alleles.

The Hardy-Weinberg equation is given by :

⇒ p² + 2pq + q² = 1

Here, p and q represent the individual allele frequencies.

Therefore, p² = frequency of homozygous condition represented by p.

q² = frequency of homozygous alleles represented by q.

and 2pq = frequency of heterozygous condition.

So, the correct answer is '2pq'.

⇒ (aa) q² = 0.000081,

⇒ (a) q = 0.009,

⇒ (A) p = 0.991,

⇒ (Aa) 2pq,

⇒ 0.018.

To learn more about heterozygous carriers here

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