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I am Lyosha [343]
3 years ago
13

When you are moving up at a constant speed in an elevator, there are two forces acting on you: the floor pushing up on you (F1)

and gravity pulling down (F2).
What's the relation of the magnitude of F1 and F2?

Physics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

F₁ = F₂

Explanation:

Given that

floor pushing up on you  by force F₁

gravity pulling down by force F₂

From second law of Newton's

F₁ - F₂ = m a

But here given that ,elevator is moving with constant speed .It means that acceleration of the elevator is zero.

a= 0 m/s²

F₁ - F₂ = m  x 0

F₁ = F₂

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Anastaziya [24]

Answer:

1.17 x 10^2 L

Explanation:

We can find the volume of the gas by using the ideal gas law:

pV=nRT

where we have:

p=792 Torr \cdot \frac{1 atm}{760 Torr} = 1.04 atm is the pressure

V is the volume

n = 4.8 mol is the number of moles

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T=37^{\circ}+273 =310 K is the temperature

Solving the equation for V, we find the volume

V=\frac{nRT}{p}=\frac{(4.8 mol)(0.0821 L atm/mol K)(310 K)}{1.04 atm}=117.5 L = 1.17\cdot 10^2 L

4 0
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The acceleration of the object after 3 seconds of fall is -9.8 m/s².

The given parameters;

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The acceleration of the object after 3 seconds of fall is calculated as follows;

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Thus, the acceleration of the object after 3 seconds of fall is -9.8 m/s².

Learn more here: brainly.com/question/13197713

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plz rate me  brainliest

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