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I am Lyosha [343]
3 years ago
13

When you are moving up at a constant speed in an elevator, there are two forces acting on you: the floor pushing up on you (F1)

and gravity pulling down (F2).
What's the relation of the magnitude of F1 and F2?

Physics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

F₁ = F₂

Explanation:

Given that

floor pushing up on you  by force F₁

gravity pulling down by force F₂

From second law of Newton's

F₁ - F₂ = m a

But here given that ,elevator is moving with constant speed .It means that acceleration of the elevator is zero.

a= 0 m/s²

F₁ - F₂ = m  x 0

F₁ = F₂

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Answer:

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Explanation:

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¹/₂Kx² = mg(h +x)

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K.E = E - W

K.E = 113.19 J - 42.6 J

K.E = 70.59 J

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KE =  ¹/₂mv²

70.59 =  ¹/₂ x 2.1 x v²

70.59 = 1.05v²

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8 0
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