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I am Lyosha [343]
2 years ago
13

When you are moving up at a constant speed in an elevator, there are two forces acting on you: the floor pushing up on you (F1)

and gravity pulling down (F2).
What's the relation of the magnitude of F1 and F2?

Physics
1 answer:
WARRIOR [948]2 years ago
6 0

Answer:

F₁ = F₂

Explanation:

Given that

floor pushing up on you  by force F₁

gravity pulling down by force F₂

From second law of Newton's

F₁ - F₂ = m a

But here given that ,elevator is moving with constant speed .It means that acceleration of the elevator is zero.

a= 0 m/s²

F₁ - F₂ = m  x 0

F₁ = F₂

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Vlada [557]

Answer:

Vmax=11.53 m/s

Explanation:

from conservation of energy

      E_A} =E_{B}

     Spring potential energy =potential energy due to elevation

   0.5*k*x²= mg(h_{B}-h_{A} )=mgh

   0.5*k*2.3²= 430*9.81*6

         k=9568.92 N/m

For safety reason

                                 k"=1.13 *k= 1.13*9568.92

                                    k"=10812.88 N/m

agsin from conservation of energy

      E_A} =E_{C}

    spring potential energy=change in kinetic energy

   0.5*k"*x²=0.5*m*V_{max}^{2}

      10812.88 *2.3²=430*V_{max}^{2}

           V_{max}=11.53 m/s

5 0
3 years ago
Who invented the wedge simple machine and why?
Lelu [443]

Answer:

Gene Sarazen began to win tournaments in 1935 with a new club he had invented that was specialized for sand play. He is hailed as the inventor of the sand wedge.

Explanation:

A wedge is a triangular shaped tool, and is a portable inclined plane, and one of the six classical simple machines. It can be used to separate two objects or portions of an object, lift up an object, or hold an object in place. It functions by converting a force applied to its blunt end into forces perpendicular (normal) to its inclined surfaces. The mechanical advantage of a wedge is given by the ratio of the length of its slope to its width.[1][2] Although a short wedge with a wide angle may do a job faster, it requires more force than a long wedge with a narrow angle.

The force is applied on a flat, broad surface. This energy is transported to the pointy, sharp end of the wedge, hence the force is transported.

The wedge simply transports energy and collects it to the pointy end, consequently breaking the item. In this way, much pressure is put on a thin area.

3 0
3 years ago
What layer is above the troposphere
goldenfox [79]
The stratosphere is the layer above the troposphere 
6 0
3 years ago
Read 2 more answers
You are traveling at 100 km/hr to make it to work on time. You have to be to work in .25 hr or you will be late. You have 16 km
alexgriva [62]

Answer: Yes

Explanation:

Velocity V is defined as the distance traveled d in a specific time t:

V=\frac{d}{t}

If you are traveling at V=100 km/h a distance d=16 m, then the time it will take you to be at work is:

t=\frac{d}{V}=\frac{16 km}{100 km/h}

t=0.16 h

This means you will make it on time, because this time is less than 0.25 h.

4 0
3 years ago
A child of mass 40.0 kg is in a roller coaster car that travels in a loop of radius 7.00 m. at point a the speed of the car is 1
pav-90 [236]
I attached the missing picture.
The force of seat acting on the child is a reaction the force of child pressing down on the seat. This is the third Newton's law. The force of a child pressing down the seat and the force of the seat pushing up on the child are the same.
There two forces acting on the child. The first one is the gravitational force and the second one is centrifugal force. In this example, the force of gravity is always pulling down, but centrifugal force always acts away from the center of circular motion.
Part A
For point A we have:
F_a=F_cf-F_g
In this case, the forces are aligned, centrifugal is pointing up and gravitational is pulling down.
F_a=m\frac{v^2}{r}-mg=179 $N
Part B
At the point, B situation is a bit more complicated. In this case force of gravity and centrifugal force are not aligned. We have to look at y components of this forces, y-axis, in this case, is just pointing upward.
F=F_{cf}\cos(30)-mg=m\frac{v^2}{r}\cos(30)-mg=153.2$N
Part C
The child will stay in place at point A when centrifugal force and force of gravity are in balance:
F_g=F_{cf}\\
mg=m\frac{v^2}{r}\\
gr=v^2\\
v=\sqrt{gr}=8.29\frac{m}{s}

6 0
3 years ago
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