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lesantik [10]
1 year ago
8

WHATS THIS ANGEL PLEASE PLEASE PLEASE

Mathematics
1 answer:
IrinaK [193]1 year ago
6 0

Answer:

The answer is 68 degree

Step-by-step explanation:

here you go angel....

please mark brainliest

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Find the values of the variables for which ABCD must be a parallelogram
sleet_krkn [62]

Answer:

y=5 and x=4

Step-by-step explanation:

So,the diagonals of a parallelogram bisect each other..

therefore,we have our two eqn

4x-2=3y-1------------(i)

3y-3=3x

or,y-1=x----------(ii)

Now,simply substitute value of x in eqn (i)

4(y-1)-2=3y-1

or,4y-4-2=3y-1

or,y=5

Again,substitute y=5 in eqn (ii)

5-1=x

therefore,

x=5

Hope it helps you!!!

4 0
4 years ago
2 + 2 +2+6+5+6+6+7655566656655555565868675364363623737384949498484848448383838838337, 784484848484847488448585858585858585858585
agasfer [191]

bro what kinda mf question is this

3 0
3 years ago
Read 2 more answers
Can anyone teach me how to solve this problem
kati45 [8]
We have constructed two angles with angle measures, 30° and 50° respectively.
Recall the angle sum of a triangle is 180°; the formula for angle sum of any n-sided polygon is formulated by: 180(n - 2), where n is the number of sides.

Since we need the three angles to equal to 180, we can call the third angle x.
Hence, our equation becomes:
 
x + 30 + 50 = 180
x + 80 = 180
x = 100

Thus, our third angle is 100°
3 0
3 years ago
The mean work week for engineers in start-up companies is claimed to be about 63 hours with a standard deviation of 5 hours. Kar
Phantasy [73]

Answer:

a. Mean

b. μ = μ₀

c. 11.5%

d. Yes

Step-by-step explanation:

The given parameters are;

The mean work week for engineers, μ₀ = 63 hours

The standard deviation, σ = 5 hours

The number of engineers in Kara's sample, n = 10 engineers

The responses given by the 10 engineers are;

70; 45; 55; 60; 65; 55; 55; 60; 50; 55

a. The given information which the newly hired is hoping to find out that it is not is the <em>mean</em>

<em />

b. The null hypothesis which is that the company claim is correct, is therefore;

Null hypothesis, H₀; μ = μ₀ = 63 hours

c. Kara's mean, \overline x is found as follows;

\overline x = (70 + 45 + 55 + 60 + 65 + 55 + 55 + 60 + 50 + 55)/10 = 57

\overline x = 57 hours

The Z-score is therefore;

Z=\dfrac{\overline x-\mu }{\sigma }

Z = (57 - 63)/5 = -1.2

From the Z-table, we have;

The p-value for P(\overline x ≤ 57) =  P(Z ≤ -1.2) = 0.11507

The probability as a percentage given to one decimal place, that the mean would be as low as Kara's mean, P(\overline x ≤ 57) = 11.5%

d. Given that the percent percentage chance (11.5%) that the mean could be as low as hers (\overline x = 57 hours) is higher than 10%, she should accept the claim.

3 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT
irinina [24]

the third choice is correct


6 0
3 years ago
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