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Romashka [77]
1 year ago
4

Select the correct answer. What is the difference of the values of the two variables in this system of equations? y= 2x + 1 x +

3y = 10 O A. 0 B. 1 KD C. 2 KD D. 3
Mathematics
1 answer:
harkovskaia [24]1 year ago
6 0

According to the given data we have the following equation:

2x + 1 x + 3y = 10

There are two types of variables in the equation above.

The variable x and the variable y

In order to calculate the difference of the values of the two variables we would make the following:

First we would sum elements of variable x

variable x=2x + 1x=3x

variable y=3y

Therefore, the difference of the values=3x-3y=0

So, The right answer would be A, the value is 0.

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M∠9 = 6x and m∠11 = 120, find the value x so that line c is parallel to line d
ASHA 777 [7]
If line c is parallel to line d, the measure of angle 9 should be the same as angle 11 according to the Corresponding angles postulate. I<span>f a transversal (line b in this case) intersects two lines (lines c and d) and the corresponding angles are congruent, then the lines are parallel.

So now since the m</span>∠11 is 120 and m∠11 is congruent to m∠9 then we can solve for x. 

m∠9 = 6x
m∠11 = 120
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6x = 120

Divide both sides by 6 to get x. 

6x/6 = 120/6
x = 20

The answer is then A. </span>
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3 years ago
What number is represented by the point plotted on the number line?
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Isaac is on the 4th floor of a building. If he rides an elevator up 7 floors, what floor will he be on? What integer represents
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4 years ago
two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)
nadya68 [22]

Answer:

24\sqrt{5}\ yards

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}

So side of one square is 5\sqrt{5}

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

=4*5\sqrt{5} \\=20\sqrt{5}

For second square:

A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}

The perimeter will be:

P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}

So the total fence will be: P1+P2

= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards

3 0
3 years ago
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