1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marta_Voda [28]
4 years ago
10

In the visit to the Old Folks' Home last weekend, Alice spent time chatting with Mr Han and helping him with simple chores. She

found that Mr Han is 36 years older than her. 7 years later, Mr Han will be 3 times as old as her. How old is Mr Han now?
Mathematics
JOELVEE
3 years ago
ALICE=X, HAN=36+X AFTER 7 YEARS ALICE= X+7, HAN=X+43 AFTER 7 YEARS, MR. HAN IS 36+X +7, AND HE IS 3X THE AGE OF ALICE, OR: X+43=3(X+7). SOLVING FOR X: X+43=3X+21 (DISTRIBUTE 3 TO X AND 7) FLIP FORMULA TO 3X+21=X+43 ADD -X-21 TO BOTH SIDES 2X=22 DIVIDE BOTH SIDES WITH 2 X=11 ALICE IS 11, MR. HAN IS 47 NOW AFTER 7 YEARS, ALICE IS 18 MR. HAN IS (47+7) 54 TO CHECK: 54 DIVIDED BY 3 = 18
1 answer:
Verizon [17]4 years ago
5 1

I think Mr. Han is around the 60 or 70 age.

I am really sorry that I couldn't answer this problem.  Try starting with 21 and multiply that by 3.  To check if you can do it, add 43 to the number you multiply 3 with.  Again, i am really sorry that i only wrote a hint.  Good luck finding the answer!

JOELVEE
3 years ago
cripes, you suck in math
JOELVEE
3 years ago
ALICE=X, HAN=36+X AFTER 7 YEARS ALICE= X+7, HAN=X+43 AFTER 7 YEARS, MR. HAN IS 36+X +7, AND HE IS 3X THE AGE OF ALICE, OR: X+43=3(X+7). SOLVING FOR X: X+43=3X+21 (DISTRIBUTE 3 TO X AND 7) FLIP FORMULA TO 3X+21=X+43 ADD -X-21 TO BOTH SIDES 2X=22 DIVIDE BOTH SIDES WITH 2 X=11 ALICE IS 11, MR. HAN IS 47 NOW AFTER 7 YEARS, ALICE IS 18 MR. HAN IS (47+7) 54 TO CHECK: 54 DIVIDED BY 3 = 18
JOELVEE
3 years ago
alice is 11 now, mr. han is 47 now.
You might be interested in
Name five whole numbers that can be expressed as the difference of two perfect squares. Show the math!
MAXImum [283]

Answer:

I expect 2 and4 and 6 and 8 and 10

5 0
3 years ago
Read 2 more answers
The attendance at baseball games at a certain stadium is normally distributed, with a mean of 30,000 and a standard deviation of
lakkis [162]

Answer:

a) 0.964

b) 0.500

c) 0.885

d) x \geq 32467.5

e) 0.997      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30000

Standard Deviation, σ = 1500

We are given that the distribution of attendance at stadium is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(attendance is greater than 27,300)

P(x > 27300)

P( x > 27300) = P( z > \displaystyle\frac{27300 - 30000}{1500}) = P(z > -1.8)

= 1 - P(z \leq -1.8)

Calculation the value from standard normal z table, we have,  

P(x > 27300) = 1 - 0.036 = 0.964 = 96.4\%

b) P(attendance greater than or equal to 30000)

P(x > 30000) = P(z > \displaystyle\frac{30000-30000}{1500}) = P(z \geq 0)\\\\P( z \geq 0) = 1 - P(z \leq 0)

Calculating the value from the standard normal table we have,

1 - 0.500 = 0.500 = 50\%

c) P(attendance between 27000 and 32000)

P(27000 \leq x \leq 32000) = P(\displaystyle\frac{27000 - 30000}{1500} \leq z \leq \displaystyle\frac{32000-30000}{1500}) = P(-2 \leq z \leq 1.33)\\\\= P(z \leq 1.33) - P(z < -2)\\= 0.908 - 0.023 = 0.885 = 88.5\%

P(27000 \leq x \leq 32000) = 88.5\%

e) P(attendance less than 33000)

P(x < 33000)

P( x < 33000) = P( z < \displaystyle\frac{33000 - 30000}{1500}) = P(z < 2)

Calculating the value from the standard normal table we have,

P(x < 33000)  = 0.997 = 99.7%

d) We have to find x such that:

P( X > x) = P( z > \displaystyle\frac{x - 30000}{1500}) = 0.95

Calculating the value from the standard normal table we have,

P(z = 1.645) = 0.95

Thus,

\displaystyle\frac{x - 30000}{1500} \geq 1.645\\\\x \geq 32467.5

The attendance should be greater than or equal to 32467.5 to be in the top 5% of all games.

6 0
4 years ago
PLZ HELP ME. SHOW YOUR WORK!!
ziro4ka [17]
The answer is C but there’s not really any work bc x is the ideal temp so if x is between 70 and 80 that’s what it means
3 0
4 years ago
Find the equation of the line that is perpendicular to y = –3x + 1 and passes though the point (6, 3).
JulsSmile [24]

Answer:

y = \frac{1}{3} x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 1 ← is in slope- intercept form

with slope m = - 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-3} = \frac{1}{3}, thus

y = \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (6, 3) into the partial equation

3 = 2 + c ⇒ c = 3 - 2 = 1

y = \frac{1}{3} x + 1 ← equation of perpendicular line

6 0
3 years ago
Expand (4x + 1)(x - 3) what is the answer
wariber [46]
Im pretty  sure that the answer to your problem would be
4x^2-11x-3
8 0
3 years ago
Read 2 more answers
Other questions:
  • Peggy needs to pay car insurance 2 times every year. She has divided the payment by 6 and saves that amount each month. Which ac
    10·2 answers
  • Which choice is correct..Thanks
    13·1 answer
  • PLEASE HELP! I DON'T UNDERSTAND!
    14·1 answer
  • For the given bond, whose interest rate is provided, find the semiannual interest payment and the
    8·1 answer
  • The cross country team ran 1.797 hours yesterday and 1.56 hours today. Each member of the team ran 3.4 miles every hour. How man
    8·1 answer
  • 2/3y + y - 4 = 31 what is the value of y?
    11·1 answer
  • A coin is tossed two times and the results are heads and heads. What is the probability as a percent?
    9·1 answer
  • Robert sold 6 more magazine subscriptions the second week than he sold the first week. He sold twice as many the third week as h
    15·1 answer
  • PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
    11·1 answer
  • Solve for X: 5x + 15 = 28
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!