The answer is 3x squared -11x-10
where is the question sir??
Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
x = ±√8i
x = ±2√2i
19)
x² + 3 = 0
x² = -3
x = ±√-3
x = <span>±</span>√3i
hope this helps, God bless!
Answer:
3(2+x)=0
Step-by-step explanation:
<u>Here are some vocab words:</u>
Product: Multiplication
Sum: Addition
"A number": x
3(2+x)=0
