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3 years ago

Which equation or inequality shows the relationship between the values |7| and |-7|?

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

6 0

Answer: C.)

| 7 | = | -7|

Ilya [14]3 years ago

6 0

Answer: |7|=|-7|

Step-by-step explanation: Because both of these numbers mean the absolute value of 7 so both of these numbers equal 7.

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2. Find the value of x and y rounded to the nearest tenth.

SVETLANKA909090 [29]

Using relations in a right triangle, it is found that the values of x and y are given by: x = 24, y = 46.4, given by option a.

<h3>What are the relations in a right triangle?</h3>

The relations in a right triangle are given as follows:

The sine of an angle is given by the length of the opposite side to the angle divided by the length of the hypotenuse.

The cosine of an angle is given by the length of the adjacent side to the angle divided by the length of the hypotenuse.

The tangent of an angle is given by the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

First, we start with the vertical line h that divides y, that is <u>opposite to an angle of 30º, with hypotenuse 34</u>, hence:

sin(30º) = h/34

0.5 = h/34

h = 17.

Then, h is opposite to an angle of 45º, while the hypotenuse is x, hence:

$\sin{45^\circ} = \frac{17}{x}$

$x = \frac{17}{\sin{45^\circ}}$

x = 24.

y is divided into two segments.

The first is the adjacent to the angle of 30º, while the hypotenuse is 34.

The second is adjacent to the angle of 45º, while the hypotenuse is 24.

Then:

$\cos{30^\circ} = \frac{y_1}{34}$

$y_1 = 34\cos{30^\circ} = 29.4$

$\cos{45^\circ} = \frac{y_2}{24}$

$y_2 = 24\cos{45^\circ} = 17$

Then, the value of y is given by:

$y = y_1 + y_2 = 29.4 + 17 = 46.4$ .

More can be learned about relations in a right triangle at brainly.com/question/26396675

#SPJ1

4 0

2 years ago

GIVING BRAINLIEST TO WHOEVER ANSWERS FIRST! ASAP<br><br>Answer 2 and 3 that's all!

stira [4]

X - 0, 1, 2, 3
y - 0, 1.5, 3, 4.5

5 0

3 years ago

Complete the table below.<br> HeLPP ILL GIVE BRAINLIEST!

makkiz [27]

Here...see the attachment

6 0

3 years ago

Read 2 more answers

If there are 10 billion transistors (each of a square shape) uniformly (without space) distributed on a silicon chip with the sq

Karo-lina-s [1.5K]

Answer:

the transistors have L=1 mm of linear size

Step-by-step explanation:

For the silicon chip the area is A=1 cm² and for the transistors the area is At=L² (L=linear size) . Then since N= 10 billion transistors of area At should fit in the area A

A=N*At

A=N*L²

solving for L

L= √(A/N)

Assuming that 1 billion=10⁹ (short scale version of billion), then

L= √(A/N) = √(1 cm²/10⁹) = 1 cm / 10³ = 1 mm

then the transistors have L=1 mm of linear size

4 0

3 years ago

Plzzzz help me with one and two I don’t understand

Ratling [72]

What this question simply asks about is you write the numbers it gave you in only one digit by 10 to the power of n. Where n represents the number of shifts of the decimal point.
And to get this number to be one digit, then you have to approximate.
To approximate; you should always consider that less than 5 counts zero and 5 or more counts+1.
Example:
5.3 is approximately 5
5.5 is approx. 6
5.9 is also approx. 6
and so on.
So the final answers are;
1) 4*10^13
2) 5*10^-11
Please note that 10^positive integer will cause the decimal point to move to the right which means a number greater than 1, usually, while 10^negative integer means number smaller than 1, usually.
Hope this helps.

7 0

3 years ago