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marishachu [46]

1 year ago

12

suppose that a set of scores has a mean of 5 and standard deviation of 2. what score corresponds to a z score of -2.0?

1 answer:

anzhelika [568]1 year ago

5 0

The set of scores has a mean of 5 and a standard deviation of 2. The score which corresponds to a z score of -2.0 is 1.

Given in the question,

Mean (m) = 5

Standard deviation σ =2

Z-score = -2

The score x,

= Z = x - m / σ

= -2 = x - 5 / 2

= -4 = x - 5

= x = 1

Standard deviation in statistics means the amount of dispersion or variations in the set of values. A lower standard deviation means the value is closer to the mean while a higher standard deviation means the value is farther away from the mean.

To learn more about standard deviation, mean, median, and mode,

brainly.com/question/27878918

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Which ordered pair is a solution of the inequality?

Greeley [361]

Answer:

<h2>d. (3, -11)</h2>

Step-by-step explanation:

$y-1$

8 0

3 years ago

Gianna is going to throw a ball from the top floor of her middle school. When she throws the hall from 48 feet above the ground,

vazorg [7]

Answer:

So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

Step-by-step explanation:

The height h of the ball is modeled by the following equation

$h(t)=-16t^2+32t+48$

The problem want you to find the times the ball will be 48 feet above the ground.

It is going to be when:

$h(t) = 48$

$h(t)=-16t^{2}+32t+48$

$48=-16t^{2}+32t+48$

$0=-16t^{2}+32t+48 - 48$

$16t^{2} - 32t = 0$

We can simplify by 16t. So

$16t(t-2)= 0$

It means that

16t = 0

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or

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So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.

6 0

3 years ago

What is the coefficient of the x5y5-term in the binomial expansion of (2x – 3y)10? 10C5(2)5(3)5 10C5(2)5(–3)5 –10C5(2)5(–3)5 10C

butalik [34]

ANSWER

$10C_5(2)^{5}( - 3)^5$

EXPLANATION

The given binomial expansion is:

${(2x - 3y)}^{10}$

Compare this to

${(a + b)}^{n}$

we have a=2x , b=-3y and n=10

We want to find the coefficient of the term

${x}^{5} {y}^{5}$

This implies that, r=5.

The terms in the expansion can be obtained using

$T_{r+1}=nC_ra^{n-r}b^r$

We substitute the given values to obtain;

$T_{5+1}=10C_5(2x)^{10-5}( - 3y)^5$

$T_{6}=10C_5(2x)^{5}(3y)^5$

$T_{6}=10C_5(2)^{5}( - 3)^5 {x}^{5} {y}^{5}$

Hence the coefficient is;

$10C_5(2)^{5}( - 3)^5$

5 0

3 years ago

Read 2 more answers

Kinda confused on this question.

salantis [7]

6x+5= 9x-4
9=3x
3=x
To find RS you need to substitute x back into the equation
9(3)-4
27-4
23

23 is the answer

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