Please help me understand this question, i’ve been struggling with this for 10minutes!

Mathematics

1 answer:

icang [17]1 year ago

7 0

Given that, for x>3, f(x)=-1.

Therefore, f(5)=-1.

Also, given that for x=3, f(x)=-2x+2

Therefore,

$\begin{gathered} f(3)=-2(3)+2 \\ f(3)=-6+2 \\ f(3)=-4 \end{gathered}$

Therefore, f(3)=-4.

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The coordinates of AB are A(-5, -1) and B(-2, -6). If AC : CB = 3 : 7, what are the coordinates of point C?

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$\text{Let the coordinates of AB are }A(-5,-1), \text{ and }B(-2, -6)\\
\\
\text{let the coordinate of th point C be (x, y), such that}\\
\\
AC:CB=3:7\\
\\
\text{By the section formula, we know that if P(x,y) lies on a line segment AB}\\
\text{where, }A(x_1,y_1), \ B(x_2,y_2)\text{ and satisfy the ratio, }AP:PB=m:n, \text{ then}$

$P=\left ( \frac{mx_2+nx_1}{m+n}, \ \frac{my_2+ny_1}{m+n} \right ).\\
\\
\text{So using this formula, we get for the given problem}\\
\\
C=\left ( \frac{3(-2)+7(-5)}{3+7}, \ \frac{3(-6)+7(-1)}{3+7} \right )\\
\\
\Rightarrow C=\left ( \frac{-6-35}{10}, \ \frac{-18-7}{10} \right )\\
\\
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\\
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miss Akunina [59]

See the picture attached with letters to better understand the problem

in the right triangle ABD
applying the Pythagoras theorem
8²=AD²+(x+4)²-----> AD²=64-(x+4)²------> equation 1

in the right triangle ADC
applying the Pythagoras theorem
12²=AD²+(2x+1)²-----> AD²=144-(2x+1)²------> equation 2

equate equation 1 and equation 2
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using a graph tool----> to resolve the second order equation
see the attached figure N 2
the solution is
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