Let j = Jake's age.
Because Mallory is 2 years older than three times Jake, Mallory's age is
3j + 2.
Answer: Mallory's age is 3j + 2
Well let’s see...
If she practices 3/4 of an hour a week we need to find out how much time is 3/4 of an hour. To do this we divide 60/4 and get 15. We check by multiplying 15 x 4 and get 60 so we know we are correct.
Now we know that 1/4 of an hour is 15 minutes, but we need to know how long she practices per session. Because 15 is 1/4 we multiply 15 x 3 to make it 3/4.
15 x 3 is 45. We check by dividing 45 by 3 and we do get 15 so we are correct.
If 3/4 of an hour is 45 minutes and she practices for 3/4 of an hour then we know that for every session she practices for 45 minutes.
The question states that she practices for 3 hours every week, since we know that we need to multiply 45 (because she practices 45 minutes every session) by a number that will get us 3 hours.
45 x 4 is 180 minutes (or three hours) we divided 180 by 4 and got 45 thus we are correct.
Which in turn means she has done 4 sessions this week. Since now we know that 4 sessions is 3 hours (making the ratio 4:3) we can multiply to find how many sessions she has left to do this week.
So if we have 4:3 then we can make it 8:6 (which means we know have 8 sessions and 6 hours) now we can make it 12:9 (12 sessions and 9 hours) and add it once more to get 16:12 (or 16 sessions and 12 hours).
Now we know that it takes 16 sessions for her to reach twelve hours, and since she and already done 4 sessions and 3 hours, it means that she has 12 sessions left to do until she is able to get her 12 hour a week goal.
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Hope this helped, have a great day! :D
When we write a line equation in the form

m is the slope of the line, and q is the y-intercept.
Since we want the y-intercept to be -3, our line will look like

In order to fix the slope, remember that two parallel lines have the same slope. So, the slope of the given line y=2x-5 is 2, and since we want a line parallel to this line, our slope will be 2 as well.
Plugging the values, we can finish the equation:
