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Rufina [12.5K]
3 years ago
11

The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 – 5t2, where t is the tim

e in seconds. A high-speed camera is ready to film the person between 15 m and 10 m above the ground. For which interval of time should the camera film the person
Mathematics
2 answers:
Nostrana [21]3 years ago
8 0

Answer:

\sqrt{2} - 1

Step-by-step explanation:

h = 20 – 5t2 = 15 -> t = 1

h = 20 – 5t2 = 10 -> t = \sqrt{2}

interval  \sqrt{2} - 1

natta225 [31]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Elan Coil [88]

the answer to the question is 4

5 0
4 years ago
Write the product of 0.4. X 0.4 x 0.4 in exponential form
Mama L [17]

Answer:

(.4) ^3

Step-by-step explanation:

0.4. X 0.4 x 0.4

We are multiplying 3 of the number .4 's together

The number 3 is the exponent

(.4) ^3

3 0
4 years ago
Read 2 more answers
HELP ASAP (MATH)
alexdok [17]

PART - A : tent - 1 volume = 400 cubic ft

Tent -2 volume = 384 cubic ft.

PART - B : I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume

<u>Step-by-step explanation:</u>

PART - A:

tent 1 :

 Base = 10 x 10ft

 Height= 12 ft

 Volume = (1/3) (10x 10) (12)

 = (1/3) (100) (12)

= 400 cubic ft.

Tent 2:

 Base = 12 x 12 ft

 Height= 8 ft.

 Volume = (1/3) (12 x 12) (8)

= 384 cubic ft.

PART - B:

I recommend Joe to make the tent -1 with base 10x10 ft. as it has more volume

 

8 0
4 years ago
Square RSTU is inscribed in circle P. Given the coordinates for the vertices of the square, find the equation of circle P.
svlad2 [7]

Answer:

(x-2)^2+y^2=20

Step-by-step explanation:

We want to find the equation of a circle P, and we know that the square RSTU is inscribed in the circle, this means that if we replace the points:

R(0,4) S(6,2) T(4,-4) and U(-2,-2) the equation must be verified.

Then, we have to replace the points in each option to see which one is the correct answer.

Option A: (x-2)^2+y^2=68

  • R(0,4):

(x-2)^2+y^2=68\\(0-2)^2+4^2=68\\(-2)^2+16=68\\4+16=68\\20\neq 68

We can see that R doesn't belong to the equation of the circle.

We could replace the rest of the points in the equation, but since we already know that R does not belong to the circle, we already know that it is not the right option.

Option B: (x+2)^2+y^2=20

  • R(0,4):

(x+2)^2+y^2=20\\(0+2)^2+4^2=20\\2^2+4^2=20\\4+16=20\\20=20

The point R(0,4) verifies the equation.

  • S(6,2):

(x+2)^2+y^2=20\\(6+2)^2+2^2=20\\8^2+4^2=20\\64+16=20\\80\neq 20

The point S doesn't belong to the equation of the circle, then we already know that this isn't the correct option.

Option C: (x-2)^2+y^2=20

  • R(0,4):

(x-2)^2+y^2=20\\(0-2)^2+4^2=20\\(-2)^2+16=20\\4+16=20\\20=20

The point R verifies the equation.

  • S(6,2):

(x-2)^2+y^2=20\\(6-2)^2+2^2=20\\4^2+4=20\\16+4=20\\20=20

The point S verifies the equation.

  • T(4,-4):

(x-2)^2+y^2=20\\(4-2)^2+(-4)^2=20\\2^2+16=20\\4+16=20\\20=20

The point T verifies the equation.

  • U(-2,-2):

(x-2)^2+y^2=20\\(-2-2)^2+(-2)^2=20\\(-4)^2+4=20\\16+4=20\\20=20

The point U verifies the equation.

<em>We can see that the four points RSTU verifies the equation. This means that the square RSTU is inscribed in circle P whose equation is: </em>(x-2)^2+y^2=20

<em>We can see that the graph of the equation verifies the answer.</em>

3 0
4 years ago
Find the solution of this system of equations.
beks73 [17]
<span>x= -8 + y
-9x + 6y= 9

substitute </span>x= -8 + y into -9x + 6y= 9

-9x + 6y= 9
-9(-8 + y) + 6y= 9
72 - 9y + 6y = 9
-3y = -63
    y = 21

<span>x= -8 + y
</span><span>x= -8 + 21
x = 13

solution (13, 21)</span>
7 0
3 years ago
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