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3 years ago

I need an answer for this question

Mathematics

1 answer:

Lerok [7]3 years ago

8 0

D I am pretty sure that it is D

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Find all solutions to this equation please

Elena L [17]

Answer:

○ d. $\displaystyle \frac{5}{8}, \frac{35}{8}, \frac{45}{8}, \frac{75}{8}$

Step-by-step explanation:

<em>See my above explanation</em>

I am joyous to assist you anytime.☺️

3 0

3 years ago

Read 2 more answers

The area of the triangle

hram777 [196]

Area=1/2 times base times height
base=4
height=3
area=1/2 times 4 times 3
area=2 times 3
area=6 square units

8 0

3 years ago

Add the product of 5 and 6 with the product of 3 and 7

xz_007 [3.2K]

It is 51.

5x6=30

3x7=21

30+21=51

Hope that I was of help.

5 0

3 years ago

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Last Question<br> (You can ignore this sentence)

Harrizon [31]

3y-20+x+13=3x+9
3y-20+x+13+2y=180

3y-7+x=3x+9
3y=2x+16
y=2/3x+16/3

5y+x=187
5(2/3x+16/3)+x=187
10/3x+80/3+x=187
13/3x=481/3

x=37

5 0

3 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.

$h^-^1\ o\ h$

$\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x$

Now substitute (-3) in place of (x),

$=-3$

8 0

3 years ago