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bija089 [108]
1 year ago
14

Parallelogram PQRS with PS = -1 + 4x and QR = 3x + 3. What is the length of QR?

Mathematics
1 answer:
Nastasia [14]1 year ago
6 0

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

PQRS

PS = -1 + 4x

QR = 3x + 3

QR = ?

Step 02:

PS = QR

-1 + 4x = 3x + 3

4x - 3x = 3 + 1

x = 4

QR = 3(4) + 3

= 12 + 3

= 15

The answer is:

QR = 15

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System of Equations Problem
aksik [14]

Sarah bought 3 first class tickets and 7 coach tickets.

Step-by-step explanation:

Given,

Number of people = 10

Total amount spent on tickets = $4830

Cost of each coach ticket = $270

Cost of each first class ticket = $980

Let,

x be the number of coach tickets

y be the number of first class tickets

According to given statement;

x+y=10      Eqn 1

270x+980y=4830   Eqn 2

Multiplying Eqn 1 by 270

270(x+y=10)\\270x+270y=2700\ \ \ Eqn\ 3\\

Subtracting Eqn 3 from Eqn 2

(270x+980y)-(270x+270y)=4830-2700\\270x+980y-270x-270y=2130\\710y=2130

Dividing both sides by 710

\frac{710y}{710}=\frac{2130}{710}\\y=3

Putting y=3 in Eqn 1

x+3=10\\x=10-3\\x=7

Sarah bought 3 first class tickets and 7 coach tickets.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/96882
  • brainly.com/question/96535

#LearnwithBrainly

5 0
3 years ago
In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
3 years ago
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