<span>8 minutes 20 seconds.
First, lets determine who many miles per minute each vehicle moves by dividing each speed by 60.
Speeder = 60 / 60 = 1 mile per minute.
Police = 75 / 60 = 1.25 miles per minute.
Other car = 45 / 60 = 0.75 miles per minute.
Since the speeding car moves for 5 minutes before the police start to chase, that means that the speeding car will now be 5 + T miles down the road with T being the time the police has been chasing. The police will be 1.25 T. We're looking for when those two equations equal each other. So
5 + T = 1.25 T
Subtract T from both sides
5 = 0.25T
Divide both sides by 0.25
20 = T
So it will take the police officer 20 minutes to catch up to the speeder. And they will both have traveled a total distance of 25 miles from the point where the speeder passed the police car.
Now we need to figure out how far the law obeying car has moved during those 25 minutes. So
25 * 0.75 = 18.75 miles.
The distance the law obeying car needs to travel to catch up to the police officer then becomes
25 - 18.75 = 6.25 miles.
The number of minutes that the law obeying car needs to travel that distance is
6.25 / 0.75 = 8.333....
Which is 8 minutes 20 seconds.</span>
To put in into y=mx+b format, you have to subtract the x on both sides.
y=-x-5
This would be the answer.
Answer:
Step-by-step explanation:
The given numbers are
We need to find the sum of the two largest numbers in the list.
The values of each number are
Using these we can say that
It means two largest numbers in the list are 
.
The sum of these two number is
Therefore, the sum of the two largest numbers in the list is .
A. 25-3x=40
3x=40-25
3x= 15
X = 5
B.1/3(x-10)=-4
1/3x - 10/3 = -4
1/3x = -4 + 10/3
X= -2/3
