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elixir [45]
3 years ago
9

The monthly use, in kilowatt hours, for two neighbors is shown in the box plots below. Which statement accurately compares the t

wo data set? check all that apply.
Neighbor 1 tends to use fewer kilowatt hours each month.

the median value for neighbor 2 is 75 kilowatt hours greater than the median value for neighbor 1.

Neighbor 1 had a greater variability in the number of kilowatt hours used per month.

Neighbor 2 had greater variability in the number of kilowatt hours used per month.

Neighbor 2 tends to use fewer kilowatt hours each month.

The median value for neighbor 2 is 50 kilowatt hours greater then the median value for neighbor 1.
Mathematics
2 answers:
icang [17]3 years ago
5 0

Answer:

Neighbor 1 tends to use fewer kilowatt hours each month.

Neighbor 2 had greater variability in the number of kilowatt hours used per month.

the median value for neighbor 2 is 75 kilowatt hours greater than the median value for neighbor 1.

Read more on Brainly.com - brainly.com/question/10714859#readmore

Step-by-step explanation:

Harlamova29_29 [7]3 years ago
3 0

Neighbor 1 tends to use fewer kilowatt hours each month.

Neighbor 2 had greater variability in the number of kilowatt hours used per month.

the median value for neighbor 2 is 75 kilowatt hours greater than the median value for neighbor 1.

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A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is
stealth61 [152]

Answer:

a) On this case we are interested on the population proportion of students that have a GPA of 3.00 or below.

b) z=\frac{0.15 -0.2}{\sqrt{\frac{0.2(1-0.2)}{200}}}=-1.77  

p_v =P(z  

c) Null hypothesis:p\geq 0.2  

Alternative hypothesis:p  

d) The significance level provided is \alpha=0.05. If we compare the  p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the population proportion of students that have a GPA of 3.00 or below is significantly lower than 0.2.  

Step-by-step explanation:

Data given and notation n  

n=200 represent the random sample taken

X=30 represent the  students with a GPA of 3.00 or below.

\hat p=\frac{30}{200}=0.15 estimated proportion of  students with a GPA of 3.00 or below.  

p_o=0.2 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

a. In testing the university's belief, how does on define the population parameter of interest?

On this case we are interested on the population proportion of students that have a GPA of 3.00 or below.

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of graduates with GPA of 3.00 or below is less than 0.2.:  

Null hypothesis:p\geq 0.2  

Alternative hypothesis:p  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

b. The value of the test statistics and its associated p-value are?

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.15 -0.2}{\sqrt{\frac{0.2(1-0.2)}{200}}}=-1.77  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

Since is a one left tailed test the p value would be:  

p_v =P(z  

c. In testing the university's belief, the appropriate hypothesis are?

Null hypothesis:p\geq 0.2  

Alternative hypothesis:p  

d. At a 5% significance level, the decision is to?

The significance level provided is \alpha=0.05. If we compare the  p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the population proportion of students that have a GPA of 3.00 or below is significantly lower than 0.2.  

5 0
3 years ago
What is the equation of the line that is perpendicular to y=2x+4 and passes through the points (4 6)
Anuta_ua [19.1K]

Answer:

y=-0.5x+8

Step-by-step explanation:

Opposite reciprocal of 2: -0.5

6=-0.5*4+b

6=-2+b

b=8

6 0
3 years ago
A triangle has angles that measure 72.5 degrees and 32.7 degrees. What is the measure of the third angle?
astraxan [27]
72.5+32.7= 105.2
Triangle angles have to equal 180
180-105.2= 74.8
Third angle= 74.8 degrees
8 0
3 years ago
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Explain how to write and solve an equation to find an unknown side length of a rectangle when given the perimeter
ratelena [41]
P=2(L+W)
if given one side and the perimiter
(P/2)-L=W
(P/2)-W=L
4 0
3 years ago
12. In a certain cafe, all the sandwiches and drinks are priced the
kakasveta [241]

The cost of one sandwich is $3.90

The cost of one deknk is $1.50

hopefully this is correct

7 0
3 years ago
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