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elixir [45]
3 years ago
9

The monthly use, in kilowatt hours, for two neighbors is shown in the box plots below. Which statement accurately compares the t

wo data set? check all that apply.
Neighbor 1 tends to use fewer kilowatt hours each month.

the median value for neighbor 2 is 75 kilowatt hours greater than the median value for neighbor 1.

Neighbor 1 had a greater variability in the number of kilowatt hours used per month.

Neighbor 2 had greater variability in the number of kilowatt hours used per month.

Neighbor 2 tends to use fewer kilowatt hours each month.

The median value for neighbor 2 is 50 kilowatt hours greater then the median value for neighbor 1.
Mathematics
2 answers:
icang [17]3 years ago
5 0

Answer:

Neighbor 1 tends to use fewer kilowatt hours each month.

Neighbor 2 had greater variability in the number of kilowatt hours used per month.

the median value for neighbor 2 is 75 kilowatt hours greater than the median value for neighbor 1.

Read more on Brainly.com - brainly.com/question/10714859#readmore

Step-by-step explanation:

Harlamova29_29 [7]3 years ago
3 0

Neighbor 1 tends to use fewer kilowatt hours each month.

Neighbor 2 had greater variability in the number of kilowatt hours used per month.

the median value for neighbor 2 is 75 kilowatt hours greater than the median value for neighbor 1.

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Step-by-step explanation:

Given that

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Since C is a cirlce centered at the origin (0, 0), with radius r = 3, it takes the form

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Because

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That is

x² + y² = 9

The vector parametric equation r(t) is therefore given as

r(t) = <x(t), y(t)>

= <3cost, 3sint>

For 0 ≤ t ≤ 2π

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