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Anon25 [30]
1 year ago
7

Which of the following does not describe the graph below?A. The y-intercept is (0, -3).B. The x-intercept is (6, 0).C. The slope

is 1/2.D. The change in the y-values is 6, & the change in the x-values is 3.

Mathematics
1 answer:
Anastaziya [24]1 year ago
8 0

D.

1) Looking attentively at the graph

The following option does not describe

Let's check the slope

The option that does not describe is

D.

Because the

A, B and C are true.

And the change in the y values is -3, and the change in x- value is 6.

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Polygons ! ( picture included)
mariarad [96]

Answer:

B

Step-by-step explanation:

2x+x=180

3x=180

x=60

2x=120

so B

hope that helps if it does please mark mine as brainliest.

8 0
3 years ago
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Find the value of Z.<br> A)7<br> B)9<br> C)11<br> D)12
Gala2k [10]
As per the isosceles triangle theorem, if the two base angles are congruent then the legs are also congruent, so we must set the two legs equal to each other:

2z - 15 = 9

Add 15 to both sides:

15 - 15 = 0
15 + 9 = 24

Divide 2 from each side:

2z = 24

2z/2 = z

24/2 = 12

z = 12

Hence, the answer would be D: z = 12

4 0
3 years ago
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Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
What is 1/5 divided by 1/2
Len [333]
The answer to your question is 0.1
4 0
3 years ago
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Equation<br> horizontal asymptote<br> vertical asymptote
ira [324]

Answer:

Hello,

In order to determine which is the horizontal asymptote remember that the horizontal is always x= something and remember that horizontal is straight from left to right.

So Horizontal asymptote = 2

For vertical asymptote it goes from the bottom of the graph, directly up. Think about it like this, you stand upright...or vertically right? So the vertical asymptote is

y= 0

Rate positively and give brainlist

3 0
3 years ago
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