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zalisa [80]
1 year ago
9

Find the value of x and y that make the quadrilateral

Mathematics
1 answer:
vitfil [10]1 year ago
4 0

The quadrilateral have equal opposite sides, for example:

Then, (4x + 6) must be equal to (7x - 3), and (4y - 3) is equal to (3y + 1), therefore

4x+6=7x-3

We can solve that equation for x

\begin{gathered} 4x+6=7x-3 \\  \\ 3x=9 \\  \\ x=\frac{9}{3}=3 \end{gathered}

Hence, x = 3. Now let's solve the other equation

\begin{gathered} 4y-3=3y+1 \\  \\ y=4 \end{gathered}

Then the value of y is 4.

Final answers:

x = 3

y = 4

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Simplify to create an equivalent expression. 8−4(−x+5) Choose 1 answer: A 4x−12 B −4x−12 C 4x+13 D 4x+5
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Answer:

A (4x-12)

Step-by-step explanation:

Still think of PEMDAS: 8-4(-x=5)

a) Multiply -4(-x + 5)

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* -4(5) = - 20

b) Now it reads = 8 +4x - 20

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* 8 - 20 = -12

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The length of a rectangle is five times its width. The perimeter of the rectangle is at most 96 cm.
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3 years ago
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Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas
neonofarm [45]

Answer:  The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says "\frac{1}{3} times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

A=b*a

Where "b" is the length of the base  and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2

2. Charlene's rhombus:

A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2

Dividing the area calculated, you get:

\frac{135\ in^2}{15\ in^2}=9

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

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3 years ago
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