3 years ago

Select the gcf of these numbers. 25 · 5· 11 and 23· 52 · 7 a 2^2 · 3

1 answer:

7 0

The greatest common factor of the numbers is that which is the fused factors of all the numbers without the repetition of the common factors present in the given.
25·5·11 = 5·5·5·11
23·52·7 =23·2·2·13·7
Since, there are no repeated factors, the answer would be,
5·5·5·11·23·2·2·13·7
The answer unfortunately is not among the choices.

You might be interested in

Help plss.............

Svet_ta [14]

Answer:

The total cost would be 29.15$

Step-by-step explanation:

multiply 27.50 by 0.06 to get 1.65. Then add 27.50 and 1.65, to get 29.15

4 0

2 years ago

The asymptote of the function f(x) = 3x + 1 – 2 is . Its y-intercept is .

julsineya [31]

There is no asymptote
The Y-int is (0,-1)

6 0

3 years ago

Read 2 more answers

If a point is equidistant from the endpoints of a segment then so

Karolina [17]

Answer: If a point is equidistant from the endpoints of a segment, then the point is on the perpendicular bisector of the segment.

6 0

2 years ago

Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be

zalisa [80]

The true statement about R ⊂ A is (a) yes, because all the elements of set A are in set R

<h3>How to determine the set operations?</h3>

The sets are given as:

U = {x | x is a real number}

A = {x | x is an odd integer}

R = {x | x = 3, 7, 11, 27}

From the given sets, we can see that the elements in set R are odd numbers

This means that the set R is a subset of set A

This is represented as:

R ⊂ A

Hence, the true statement about R ⊂ A is (a) yes, because all the elements of set A are in set R