Select the gcf of these numbers. 25 · 5· 11 and 23· 52 · 7 a 2^2 · 3

1 answer:

7 0

The greatest common factor of the numbers is that which is the fused factors of all the numbers without the repetition of the common factors present in the given.
25·5·11 = 5·5·5·11
23·52·7 =23·2·2·13·7
Since, there are no repeated factors, the answer would be,
5·5·5·11·23·2·2·13·7
The answer unfortunately is not among the choices.

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Anna35 [415]

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2 years ago

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Secant RM intersects secant RN at point R. Find the length of RQ. If necessary, round to the hundredths place.

QveST [7]

Answer:

3 Units

Step-by-step explanation:

Secant RM intersects secant RN at point R.

The secants intersects the circle at points P and Q respectively as seen in the diagram.

To determine the length of RQ, we use the Theorem of Intersecting Secants.

Applying this on the diagram, we have:

RP x RN=RQ X RM

4(4+5)=RQ(RQ+9)

Let the length of RQ=x

$4*9=x^2+9x\\36=x^2+9x\\x^2+9x-36=0\\x^2+12x-3x-36=0\\x(x+12)-3(x+12)=0\\(x+12)(x-3)=0\\x+12=0$ x-3=0\\x=-12 or x=3\\Since x cannot be negative$\\x=|RQ|=3$