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olya-2409 [2.1K]
10 months ago
11

Find the product of two numbers whose sum is 11 and diffrence is 3

Mathematics
1 answer:
spayn [35]10 months ago
7 0

Answer:

The numbers are 4 and 7

Step-by-step explanation:

To start, we can set up two equations.

x + y = 11 and x - y = 3

We now need to solve for one of these variables in terms of the other. I am choosing to solve for x, but either way will work. I'm using the second equation and solving for x by adding y to each side, which gives me

x = 3 + y

Now that I have a value for x, I can plug this into my first equation

3 + y + y = 11

Combining like terms gives me

3 + 2y = 11

Subtracting 3 from both sides leaves

2y = 8

And dividing by 2 to solve for y gets

y = 4

We now know one number, and to solve for the other we can plug our y value into either equation

x + 4 = 11

Subtracting 4 from both sides yields the x value

x = 7

So the two numbers are 4 and 7

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Step-by-step explanation:

Step1:

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Step2:

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Consider,

P(X 6) = 1 - P(X5)

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P(X 10) = 1 - P(X9)

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