2 years ago

Which 2-digit number is equal to the sum of its first digit plus the square of its second digit?

1 answer:

8 0

Let, the two-digit number = xy

It is given that, xy = x + y²

Then, number which obey the rule is 89.

Check: 8 + 9² = 8 + 81 = 89 [ Itself ]

In short, Your Answer would be: 89

Hope this helps!

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