Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
D. 3.2
Step-by-step explanation:
Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.
Based on this theorem, we have: TV = ½(RS)
TV = 3n - 2
RS = n + 12
Substitute
3n - 2 = ½(n + 12)
Multiply both sides by 2
2(3n - 2) = (n + 12)
6n - 4 = n + 12
Collect like terms
6n - n = 4 + 12
5n = 16
Divide both sides by 5
5n/5 = 16/5
n = 3.2
Answer:
-4
Step-by-step explanation:
its closer to -4
The constant term in the equation is -20 because you will always be subtracting 20 no matter how big x is
Answer:
-7x - 6
Step-by-step explanation:
1
Distribute
(−2+5)−1(6+4)+(−7)
(−2+5)−6−4+(−7)
2
Eliminate redundant parentheses
(−2+5)−6−4+(−7)
−2+5−6−4+−7
3
Add the numbers
−2+5−6−4+−7
−2−6−6+
4
Combine like terms
−2−6−6+
Answer:
−7−6