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Harrizon [31]
3 years ago
12

The number of grams in the molar mass of an element is the same as an elements ...

Chemistry
1 answer:
rosijanka [135]3 years ago
4 0

It is the same as an elements number of protons.

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A chlorine atom in its ground state has a total of seven electrons in orbitals related to the atoms third energy level. how many
kiruha [24]
<span>5 electrons

</span>The electron configuration of an atom shows or describes the distribution of electrons in their atomic orbitals. In particular, it shows the distribution in terms of the principal energy levels or electron shells (reflected by the numbers 1, 2, 3, 4, 5, 6, 7) and their corresponding subshells (reflected by the letters s,p,d,f,g) composed of atomic orbitals. 

The maximum number of electrons in the s-subshell is 2, in the p-subshell, 6, in the d-subshell, 10, in the f-subshell, 14, and in the g-subshell, 18. In the electron configuration of an atom, the number of electrons in the subshell for a given atom is reflected by a number (in superscript) next to the corresponding letter of the subshell. 
 
<span>The electron configuration of a chlorine atom in its ground state is 
</span>1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}

Thus, the number of electrons in the 3rd energy level in the p-subshell is 5 (3p^{5} as seen in the electron configuration of the atom). 
7 0
3 years ago
Imagine a friend is planning a rock-climbing trip. Write a note in the box explaining how gas exchange is affected at the top of
wariber [46]

Answer:

Air is less dense on a mountaintop than at sea level.

Air pressure is lower at low altitudes.

As you climb a mountain, air pressure increases.

More force pushes on the air at the bottom of an air column.

As you descend a mountain, air molecules are closer together.

Explanation:

6 0
2 years ago
A wooden block has a mass of 20 g and dimensions of 5 cm x 1 cm x 1 cm.
marta [7]

Answer:

V = 5 cm³

ρ = 4 g/cm³

Explanation:

Step 1: Calculate the volume (V)

We have a wooden cuboid of dimensions 5 cm × 1 cm × 1 cm. We can calculate its volume using the following expression.

V = 5 cm × 1 cm × 1 cm

V = 5 cm³

Step 2: Calculate the density (ρ)

The density is equal to the mass divided by the volume.

ρ = m / V

ρ = 20 g / 5 cm³

ρ = 4 g/cm³

4 0
3 years ago
An aqueous solution of 1.29 M ethanol, CH3CH2OH, has a density of 0.988 g/mL. The percent by mass of CH3CH2OH in the solution is
anzhelika [568]

Answer:

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

m_{solution}=1L*\frac{1000 mL}{1L}*\frac{0.988g}{1mL} =988g

Now, the mass of the ethanol:

m_{C_2H_5OH}=(1.29molC_2H_5OH/L*1L)*\frac{46gC_2H_5OH}{1molC_2H_5OH} \\m_{C_2H_5OH}=59.34g

Finally, the by mass percent is:

m/m=\frac{59.34g}{988g}*100\\%

%m=6%

Best regards.

4 0
2 years ago
Evaluate ( a=2 b=3)...3a - 2b =​
skad [1K]

Hey!

---------------------------------------------------

Steps To Solve:

~Substitute

3(2) - 2(3)

~Subtract

6 - 6

~Simplify

0

---------------------------------------------------

Answer:

\Large\boxed{\mathsf{0}}

---------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
Read 2 more answers
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