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Alecsey [184]
3 years ago
11

A student is investigating the effect of concentration on the colour of a solution of copper sulfate.She wished to make up 250cm

^3 of a solution if copper sulfate with a concentration of 0.5 mol/dm^3 that she can dilute. a solution with the concentration of 0.50 mol/dm^3 contains 0.50 mol of copper sulfate per decimetre cubed calculate the concentration of this solutionin g/dm^3
Chemistry
1 answer:
IrinaK [193]3 years ago
3 0

Answer:

79.8g/dm³

Explanation:

As you can see, the solution in the problem contains 0.5 moles of copper sulfate per dm³. To solve this question we must convert these moles to grams using its molar mass (Molar mass CuSO4 = 159.609g/mol) as follows:

0.5mol CuSO4/dm³ * (159.609g/mol) =

<h3>79.8g/dm³</h3>
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when propene gas (C3H6) is added to bromine liquid, another liquid is produced which has the formula C3H6Br2. what is the chemic
klio [65]

Answer:

C3H6 + Br2 → C3H6Br2

Explanation:

The reaction in which C3H6Br2 (1,2-Dibromopropane) is created is:

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We can see that the only difference between the product (C3H6Br2) and the known reactant (C3H6) of the reaction is two bromine atoms (Br2). Br2 is diatomic bromine - a molecule we get after combining two bromine atoms. This compound is a red-brown liquid at room temperature, which means that that is the liquid described in your question.

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Delicious77 [7]

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Expert Verified

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6 0
3 years ago
If Kc = 4.0×10−2 for PCl3(g)+Cl2(g)⇌PCl5(g) at 520 K , what is the value of Kp for this reaction at this temperature?
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Here we have to get the K_{p} of the reaction at 520 K temperature.

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Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅

Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole

The given value of  K_{c} is 4.0×10⁻²

The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.

On plugging the values in the equation we get,

K_{p} = 4.0 X 10^{-2}(0.082X520)^{1}

Or, K_{p} = 1.705 atm

Thus, the K_{p} of the reaction is 1.705 atm

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3 years ago
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