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kicyunya [14]
1 year ago
9

A Sony television has a rectangular screen with a diagonal measurement of 18 inches If the screen has a height of 10 inches, wha

t is the length of the screen? Round to the nearest whole number.
Mathematics
1 answer:
Alexandra [31]1 year ago
4 0

Let's draw a figure from the statements in the problem. It can look like this:

The diagonal is 18 inches, the height is 10 inches and the length is <em>x inches</em>.

We can use the pythagorean theorem [ c^2 = a^2 + b^2 ] to solve this problem easily.

Looking at the top triangle, we can write:

18^2=10^2+x^2

With the help of a little algebra, let's solve for x, the length. Shown below:

\begin{gathered} 18^2=10^2+x^2 \\ 324=100+x^2 \\ x^2=324-100 \\ x^2=224 \\ x=\sqrt[]{224} \\ x\approx14.97 \end{gathered}

<em>Rounding to the nearest whole number, the </em><em>length of the screen</em> is:

15 inches

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James has a bag 77 of nickels and dimes. The total value of coins is $6.60. How many dimes does James have?
tatuchka [14]

James has 55 dimes in the bag

Step-by-step explanation:

The given is:

  • James has in a bag 77 of nickels and dimes
  • The total value of coins is $6.60

We need to find how many dimes James has

Assume that the number of nickels is x and the number of

dimes is y in the bag

∵ There are x nickels in the bag

∵ There are y dimes in the bag

∵ There are 77 coins in the bag

∴ x + y = 77 ⇒ (1)

∵ 1 nickel = 5 cents

∴ The value of nickles in the bag = 5x cents

∵ 1 dime = 10 cents

∴ The value of dimes in the bag = 10y cents

∵ The total value of coins is $6.60

∵ 1 dollar = 100 cents

∴ $6.60 = 6.60 × 100 = 660 cents

∴ 5x + 10y = 660 ⇒ (2)

Now we have a system of equations to solve it

Multiply equation (1) by -10 to eliminate y

∵ -10x - 10y = -770 ⇒ (3)

- Add equations (2) and (3)

∴ -5x = -110

- Divide both sides by -5

∴ x = 22

Substitute the value of x in equation (2) to find y

∵ 22 + y = 77

- Subtract 22 from both sides

∴ y = 55

∴ The number of dimes is 55

James has 55 dimes in the bag

Learn more:

You can learn more about the system of equations in brainly.com/question/6075514

#LearnwithBrainly

6 0
4 years ago
.5x−6=x+0.05 <br><br> Which number is equal to the value of x?
Daniel [21]
The answer to the question is x=-12.1hopes this helps you.

<span>  Step 1: subtract X from both sides.
   
 0.5x-6-x=x+0.05-x
     
-0.5x-6=0.05</span>
Step 2: Add 6 to both sides.    

 -0.5x-6+6=0.05+6
                                                 
 -0.5x=6.05
Step 3: Divide both sides by -0.5.−0.5x−0.5=6.05−0.5
7 0
3 years ago
What’s the inverse function of f(x)=4x^2-13
Cerrena [4.2K]

Answer:

. The inverse function is y=x−24 .

Step-by-step explanation:

6 0
3 years ago
Determine the domain and range of the relation {(-2, 4), (1, 3), (0, -4), (3, 2)}
djverab [1.8K]
The domain is the unique x coordinates and the range is the unique y coordinates.  The domain = -2, 0, 1, 3. The range = -4, 2, 3, 4
6 0
3 years ago
First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x
e-lub [12.9K]

Answer:

(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

\int x ln(5+x)dx

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

\int (U-5) ln(U)dU

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

\int (pq')=pq-\int qp'

so we must define p, q, p' and q':

p=ln U

p'=\frac{1}{U}dU

q=\frac{U^{2}}{2}-5U

q'=U-5

and now we plug these into the formula:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU

Which simplifies to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU

Which solves to:

\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C

so we can substitute U back, so we get:

\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C

and now we can simplify:

\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C

\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C

notice how all the constants were combined into one big constant C.

7 0
4 years ago
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