The width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
<u>Explanation:</u>
Given:
Two rectangles are proportional.
Length and width of 1 rectangle = 6 : 8
Dimensions of the other rectangle = ?
Let length and width of the other rectangle be x : y
According to the question:
So, the width of the rectangle would be 6 times the first rectangle and the length would be 8 times the first rectangle.
Answer:
denominators are zero for x=1
there is no solution
Step-by-step explanation:
We suspect your equation is supposed to be ...
10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators
The denominators will be zero for x=1.
This version of the equation has no solution. It simplifies to ...
2/(x-1) + 1/5 = 2/(x -1)
1/5 = 0 . . . . . subtract 2/(x-1) from both sides
There is no value of x that will make this equation true.
_____
<em>Alternative interpretation</em>
The way your equation is written, it must be interpreted according to the order of operations to be ...
(10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero
2x -3.8 = 2/x
2x^2 -3.8x = 2 . . . . multiply by x
2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)
(x -0.95)^2 = 1.9025
x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}
