Answer:
The measure of the arc PJ is 
Step-by-step explanation:
step 1
Find the measure of angle L
we know that
In a inscribed quadrilateral opposite angles are supplementary
so

we have

substitute


step 2
Find the measure of arc KJ
we know that
The inscribed angle measures half that of the arc comprising
so

substitute the values



step 3
Find the measure of arc PJ
we know that
The inscribed angle measures half that of the arc comprising
so

substitute the values



Answer:
1. (-3,-11),(-2,-8),(-1,-5),(0,-2)(1,1)(2,4) (3,7)
2 (-3,5),(-2,0),(-1,-3), (0,-4),(1,-3),(2,0),(3,5)
Answer:
First off, I can't solve for y, there is no y variable.
Second, 3 = 7 ( 1 - 1 ) is not true because 3 ≠ 0 ( 3 doesn't equal 0 ) :
3 = 7 ( 1 - 1 )
3 = 7 ( 0 ) ( Simplify Parenthesis )
3 = 0 ( Multiply 7 and 0 )
3 ≠ 0
Answer:
Therefore the maximum number of bouquets is 12.
Step-by-step explanation:
Given that, Angelina has 24 tulip and 36 roses.
To find the number bouquets, we need the find out the g.c.d (greatest common divisor) of 24 and 36.
24= 2×2×2×3
36=2×2×3×3
The common factors are = 2,2,3
The g.c.d of 24 and 36 is =2×2×3
= 12
Therefore the maximum number of bouquets is 12.
It may be easier to start from
.. a(x +3)(x -1) = 0
.. a(x^2 +2x -3) = 0
The quadratic
.. ax^2 +bx +c = 0 will have solutions -3 and 1 for ...
.. a ≠ 0
.. b = 2a
.. c = -3a