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3 years ago

What are the values of the digits 4,432

Mathematics

1 answer:

Neporo4naja [7]3 years ago

5 0

4000 + 400 +30 + 2 or four thousand -four hundred -thirty two.

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crimeas [40]

Answer:

Step-by-step explanation:

what is the question

8 0

2 years ago

Help me please please

artcher [175]

Answer:

L = 34 - 0.5d

21 feet

Step-by-step explanation:

The initial water level ; 34

the amount is rises per day; 0.5

"L" is the water level,

"d" is the days passed.

In order to find the water level, one will have to multiply the amount the water rises each day, by the days passed. Then one will have to subtract that from the initial water level, hence the equation formed is the following;

L = 34 - 0.5d

Substitute in 26 for "d", to solve for the water level after 26 days.

L = 34 - 0.5(26)

L = 34 - 13

L = 21

4 0

2 years ago

IM SO LOST PLEASE HELP

LiRa [457]

Check the picture below.

$\bf \textit{lateral area of a cone}\\\\
LA=\pi r\stackrel{slant-height}{\sqrt{r^2+h^2}}~~
\begin{cases}
LA=539\pi \\
r=49
\end{cases}\implies 539\pi =\pi 49\sqrt{r^2+h^2}
\\\\\\
\cfrac{539\pi }{49\pi }=\sqrt{r^2+h^2}\implies 11=\sqrt{r^2+h^2}$

3 0

2 years ago

One watering system needs about three times as long to complete a job as another warning system when both systems operate at the

algol13

Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = $3x$

Rate to complete the job by another watering system = $\frac{1}{x}\ job/min$

Rate to complete the job by One watering system = $\frac{1}{3x}\ job/min$

Rate at which both can complete the job = $\frac{1}{9}\ job/min$

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

$\frac{1}{x}+\frac{1}{3x}=\frac19$

Now taking LCM to make the denominator common we get;

$\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}$

By Cross multiplication we get;

$4\times9 =3x\\\\3x =36$

Dividing both side by 3 we get;

$\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min$

Time required by One watering system = $3x =3\times 12 =36\ min$

Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

6 0

2 years ago

Find a_4 and a_n for the arithmetic sequence. a_6= -15, a_8= -7 <br> .

kiruha [24]

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8 0

2 years ago