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Alex17521 [72]
1 year ago
6

Name three other common multiples of 8 and 12

Mathematics
1 answer:
Sladkaya [172]1 year ago
3 0

The first few multiples of 8 are: 8, 16, 24, 32, 40, and 48. The first multiples of 12 are: 12, 24, 36, 48, 60, and 72.

Common multiple of 8 and 12 are 24 and every subsequent multiple of 24.

As 8×3=24

12×2=24

So 24 is a common multiple of 8 and 12 this means the other common multiples of 8 and 12 are the multiples of 24 like 48, 72, 96 etc.

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Round 3:38 to the nearest ten
aev [14]

Answer:3

Step-by-step explanation:

Round 3.38 to the nearest ten

Rounding up to the nearest 10, we look at the digits on the left hand side of the decimal point. If the number on the right of the decimal point is less than 5, we ignore it.if it is greater than 5, we add one to the last digit on the right hand side.

In this case, the first digit on the left hand side is less than 5, so we ignore it. Rounding up to the nearest ten,the 0.38 is ignored.

Therefore, it becomes 3.0 = 3

To the nearest ten

7 0
3 years ago
Two cars leave the same parking lot, with one heading south and the other heading east. After several minutes, the southbound ca
ELEN [110]

Answer:

25

Step-by-step explanation:

6 0
3 years ago
What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?
kvasek [131]

Answer:

The center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

\left(x-a\right)^2+\left(y-b\right)^2=r^2

here,

  • r =  raduis
  • center = (a, b)

Given the equation

\left(x-14\right)^2+\left(y+21\right)^2=64

\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}

\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2

comparing with the circle equation

\left(x-a\right)^2+\left(y-b\right)^2=r^2

Therefore, the center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

7 0
2 years ago
Hallie bikes 1 5/8 km before lunch and 6 1/4 km after lunch. How much farther does Hallie bike after lunch than before lunch? Ex
EleoNora [17]

Answer:

4 \frac{5}{8} km

Step-by-step explanation:

To find how much farther Hallie biked after lunch compared to the amount she biked before lunch, we can subtract the amounts:

6 \frac{1}{4}-1\frac{5}{8}

However, we can only subtract fractions that have the same denominator, so we need to convert \frac{1}{4} to a fraction with a denominator of 8:

\frac{1}{4}=\frac{2}{8}

Now, we can't subtract 2 from 8, so we need to 'borrow' from the 6 to make the fraction larger:

6\frac{2}{8}=5\frac{10}{8}

Now subtract: 5\frac{10}{8}-1\frac{5}{8}=4\frac{5}{8}

4 0
3 years ago
Using distributive property simplify 4 (3x + 7)
marysya [2.9K]

Answer:

12x+28 I think

Step-by-step explanation:

4•3x+7

12x+(4•7)

12x+28

5 0
3 years ago
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