A 95% confidence interval for the proportion who believe immigration is a good thing is; CI = (0.4173, 0.7173)
<h3>What is the Confidence Interval of Proportions?</h3>
The formula for the confidence interval of proportions is;
CI = p ± z√(p(1 - p)/n)
where;
p is sample proportion
z is z-score at confidence level
n is sample size
We are given;
Number of success; x = 631
Sample size; n = 1095
Thus;
sample proportion; p = x/n = 631/1095 = 0.5763
The z-score at 95% confidence level is 1.96. Thus;
CI = 0.5673 ± 1.96√(0.5673(1 - 0.5673)/1095)
CI = 0.5673 ± 0.015
CI = (0.5673 - 0.15), (0.5673 + 0.15)
CI = (0.4173, 0.7173)
Read more about Confidence Interval of Proportions at; brainly.com/question/15712887
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