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3 years ago

The diameter of a Frisbee is 12 inches. what's the area of the Frisbee?

Mathematics

1 answer:

xenn [34]3 years ago

7 0

A= πr² = π × 6² = "113.1" is the area of the frisbee.

Please put me as brainliest.

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A rectangle has vertices at (0, 0), (3, 0), and (0,6). What is the area of the rectangle?

Alexxandr [17]

First, set the coordinate points on a graph, and joint them to form a graph

By looking at the graph we can see that:

width : 3

length: 6

Area of a rectangle : Length x width : 6 x 3 = 18

7 0

1 year ago

Sammi has 2 1/3 feet of rope. If he cuts the rope into pieces that are each 1/2 foot long, there will be 1/3 foot of rope left o

Stells [14]

Answer:

Step-by-step explanation:

Sammi has 2 1/3 feet of rope.

To write this type of fraction = 2 + 1/3 - The integer 2 in the expression is the amount of feet of rope that was cut.

Thus to know the number of 1/2 foot pieces produced, let this number be x. Thus, we have 1/2 of x pieces = 2

x/2 = 2; x = 2x2 = 4.

Thus, Sanmi has 4 pieces of 1/2 foot long piece each of rope.

4 0

3 years ago

A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and

mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

$\mu = \frac{3X_{1} + 4X_{2} }{8}$

Now

Bias for the estimator = E(μ bar) - μ

= $E( \frac{3X_{1} + 4X_{2} }{8}) - 4.5$

= $\frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5$

= $\frac{3(4.5) + 4(4.5)}{8} - 4.5$

= $\frac{13.5 + 18}{8} - 4.5$

= $\frac{31.5}{8} - 4.5$

= 3.9375 - 4.5

= - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

= Var(μ bar) + [Bias(μ bar, μ)]²

= $Var( \frac{3X_{1} + 4X_{2} }{8}) + 0.3136$

= $\frac{1}{64} Var( {3X_{1} + 4X_{2} }) + 0.3136$

= $\frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})] }) + 0.3136$

= $\frac{1}{64} [{3(57.76) + 4(57.76)}] } + 0.3136$

= $\frac{1}{64} [7(57.76)}] } + 0.3136$

= $\frac{1}{64} [404.32] } + 0.3136$

= $6.3175 + 0.3136$

= 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0

3 years ago

Plzz helppp i don't understand

vivado [14]

Answer:

Step-by-step explanation:

The denominators are 4, 5, and 8.

Write the prime factorizations:

4 = 2²

5 = 5

8 = 2³

To find the least common denominator, multiply the prime numbers with the highest exponents.

2³ × 5 = 40

6 0

3 years ago

Read 2 more answers

There are 6 red marbles, 5 green marbles, and 4 yellow marbles in a bag. If Joe picks 2 marbles one after the other without repl

lapo4ka [179]

The probability that both marbles will be a red color is:

6..... ⇔ number that satisfies the constraint
_____
15..... ⇔ number of outcomes

4 0

3 years ago