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zubka84 [21]
3 years ago
8

What expression could be used to determine the product of -4 and 3 1/4

Mathematics
2 answers:
nasty-shy [4]3 years ago
4 0
-4*3 1/4 or use it backwards
nikdorinn [45]3 years ago
3 0
-4*3 1/4 would be and expression you can use
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Compare the strengths and weaknesses of the horizontal and vertical methods for adding and subtracting polynomials. Include comm
Pavlova-9 [17]

Answer:

Overall vertical is visually better, if done correctly

it forces you to "line up" all the common exponents.

The disadvantage is that it usually requires re-writing the problem, and it takes up space.

most problems are presented horizontally, that becomes the issue to locate the common exponents.

in both cases the biggest issue is people forget

that when subtracting "subtracting a negative is like adding a positive"

-5x - (-8x)  = 3x [that is a positive 3x]

or:

     -7x

-    - 10x

-------------

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everyone misses those eventually so you have to watch out for that in both methods

Step-by-step explanation:

5 0
3 years ago
Select the simplification that accurately explains the following statement.
lutik1710 [3]

Answer:

Option (b) is correct.

(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}=2^{1}=2

Step-by-step explanation:

Given: (2^\frac{1}{4} )^4

We have too choose the correct simplification for the given statement.

Consider (2^\frac{1}{4} )^4

Using property of exponents, (a^m)^n=a^m\times a^m\times a^m\times ....\times (n\ times)

We have,

(2^\frac{1}{4} )^4=2^\frac{1}{4} \times 2^\frac{1}{4}\times 2^\frac{1}{4}\times 2^\frac{1}{4}

Again applying property of exponents  a^m\times a^m=a^{n+m}

We have,

(2^\frac{1}{4} )^4=2^{(\frac{1}{4}+ \frac{1}{4}+ \frac{1}{4}+ \frac{1}{4} )}

Simplify, we have,

(2^\frac{1}{4} )^4=2^{\frac{4}{4}}

we get,

(2^\frac{1}{4} )^4=2^{1}=2

Thus, (2^\frac{1}{4} )^4=2

Option (b) is correct.

   

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