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11 months ago

Is a click and drag and.

Mathematics

1 answer:

Verdich [7]11 months ago

4 0

Hi! i can’t see song central. but, song factory is more expensive than music mania because song factory is 1.75 a download and music mania is 1.50 a download

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Simplify: x^5. X-^5?

WARRIOR [948]

Answer:

i believe the answer you are looking for is 1?

Step-by-step explanation:

7 0

3 years ago

Simplify 5 to the 2nd power * 5 to the 9th power

icang [17]

Answer:

Thee first one is 25 and the second one is 1,953,125

Step-by-step explanation:

You just times each one by five. If you want to simplify it tho it would be as the first one is 12,5 the second one is 976562.5. Hope it helps

3 0

3 years ago

Read 2 more answers

Solve this application problem using a system of equations: Dan and June mix two kinds of feed for pedigreed dogs. They wish to

wlad13 [49]

Answer:

50 pounds

Step-by-step explanation:

Dan and june mix two kind of feed for pedigreed dogs

Feed A worth is $0.26 per pound

Feed B worth is $0.40 per pound

Let x represent the cheaper amount of feed and y the costlier type of feed

x+y= 70..........equation 1

0.26x + 0.40y= 0.30×70

0.26x + 0.40y= 21.........equation 2

From equation 1

x + y= 70

x= 70-y

Substitutes 70-y for x in equation 2

0.26(70-y) + 0.40y= 21

18.2-0.26y+0.40y= 21

18.2+0.14y= 21

0.14y= 21-18.2

0.14y= 2.8

Divide both sides by the coefficient of y which is 0.14

0.14y/0.14= 2.8/0.14

y= 20

Substitute 20 for y in equation 1

x + y= 70

x + 20= 70

x= 70-20

x = 50

Hence Dan and june should use 50 pounds of the cheaper kind in the mix

4 0

3 years ago

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day. At the same rates two Nissans, four Fords, and thr

Sindrei [870]

Answer:

The rental rate for the Fords is of $12 per day.

Step-by-step explanation:

This question is solved using a system of equations.

I am going to say that:

x is the cost of a Nissan.

y is the cost of a Ford.

z is the cost of a Chevrolet.

Three Nissans, two Fords, and four Chevrolets can be rented for $106 per day.

This means that:

$3x + 2y + 4z = 106$

Two Nissans, four Fords, and three Chevrolets cost $107 per day

This means that:

$2x + 4y + 3z = 107$

Four Nissans, three Fords, and two Chevrolets cost $102 per day.

This means that:

$4x + 3y + 2z = 102$

From the first equation:

$4z = 106 - 3x - 2y$

$2z = 53 - 1.5x - y$

$z = 26.5 - 0.75x - 0.5y$

Replacing into the third equation:

$4x + 3y + 53 - 1.5x - y = 102$

$2.5x + 2y = 49$

From the second equation:

$2x + 4y + 3z = 107$

$2x = 107 - 4y - 3z$

$x = 53.5 - 2y - 1.5z$

$x = 53.5 - 2y - 1.5(26.5 - 0.75x - 0.5y)$

$x - 1.125x = 53.5 - 2y - 39.75 + 0.75y$

$-0.125x = 13.75 - 1.25y$

$0.125x = 1.25y - 13.75$

$x = \frac{1.25y - 13.75}{0.125}$

$x = 10y - 110$

Find the rental rate for the Fords.

We have to find y, so:

$2.5x + 2y = 49$

$2.5(10y - 110) + 2y = 49$

$25y - 275 + 2y = 49$

$27y = 324$

$y = \frac{324}{27}$

$y = 12$

The rental rate for the Fords is of $12 per day.

3 0

3 years ago

Paul currently has $300 to spend on a data plan. He found a phone for $100 and a $50 a month charge.

zvonat [6]

Let x= months
So 50x is the total amount he pays after x months. You went to add 100 to this because there's a fixed cost of 100 for the phone
So you have the expression 100+50x which is the amount he pays after x months
Since he has a limit of 300,
100+50x < 300

3 0

3 years ago