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weeeeeb [17]
3 years ago
6

There are 451 students at Highland Jr. High. If there are 135 more boys than girls, write and solve an equation to show how many

girls there are.
Mathematics
2 answers:
luda_lava [24]3 years ago
8 0
An Equation you can use is 
<u><em>451 - 135 = 316 / 2 = 158
</em></u>
So your answer is 158.
"AB84"
egoroff_w [7]3 years ago
7 0
451-135=316
316/2=158
so the answer is 158 girls
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WILL MARK BRAINIEST, QUESTION IS HARD, Ann works for a city’s parks and recreation department. She is looking for some commercia
MrRa [10]

Answer:

x =320

Step-by-step explanation:

Given

x^2 + 200x = 166400

Required

Find x

We have:

x^2 + 200x = 166400

Rewrite as:

x^2 + 200x - 166400 = 0

Expand

x^2 + 520x - 320x - 166400 = 0

Factorize

x(x + 520) - 320(x + 520)= 0

Factor out x + 520

(x - 320) (x + 520)= 0

Split

x - 320 = 0\ or\ x + 520= 0

Solve

x = 320\ or\ x =- 520

Side length must be positive;

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x = 320

4 0
3 years ago
The GCD(a, b) = 9, the LCM(a, b)=378. Find the least possible value of a+b.
denis-greek [22]
\mathrm{gcd}(a,b)=9\implies9\mid a\text{ and }9\mid b\implies9\mid a+b

which means there is some integer k for which a+b=9k.


Because 9\mid a and 9\mid b, there are integers n_1,n_2 such that a=9n_1 and b=9n_2, and


\mathrm{lcm}(a,b)=\mathrm{lcm}(9n_1,9n_2)=9\mathrm{lcm}(n_1,n_2)=378\implies\mathrm{lcm}(n_1,n_2)=42

We have 42=2\cdot3\cdot7, which means there are four possible choices of n_1,n_2:

1, 42
2, 21
3, 14
6, 7

which is to say there are also four corresponding choices for a,b:

9, 378
18, 189
27, 126
54, 63

whose sums are:

387
207
153
117

So the least possible value of a+b is 117.
6 0
3 years ago
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SVEN [57.7K]

Answer: (0,0)

Step-by-step explanation:

X point of origin is zero

Y point of origin is zero

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