Eliminationg these equations gives zero ,no solution
Answer:
A)
y^2-6y = 0
or, y(y-6) = 0
or, y = 0 or y = 6
B)
n^2+5n+7 = 7
or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)
or, n^2+5n = 0
or, n(n+5) = 0
or, n=0 or n= -5
C)
2t^2-14t+3 = 3
or, 2t^2-14t = 0
or, 2t(t-7) = 0
or, t=0 or t=7
D)
1/3x^2+3x-4 = -4
or, 1/3x^2+3x = 0
or, 1/3x(x+9) = 0
or, x=0 or x= -9
E)
Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.
THANK YOU FOR READING.
Answer:
y = 140, x = 159
Step-by-step explanation:
Angle y:
we can find this angle by subtracting 40 from 180, 180-40 = 140 = y
Angle x:
Some measure of an angle plus angle b is equal to 180 degrees: 180-61 = 119
We can now find the measure of the third angle of the triangle: 180-(119+40) = 21
The third angle plus angle x is equal to 180: 180-21 = 159 = x
Answer:
y = 2x + 7
Step-by-step explanation:
Find the slope with y2-y1/x2-x1, which is 2
Find y intercept, which is 7
