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weeeeeb [17]
2 years ago
6

There are 451 students at Highland Jr. High. If there are 135 more boys than girls, write and solve an equation to show how many

girls there are.
Mathematics
2 answers:
luda_lava [24]2 years ago
8 0
An Equation you can use is 
<u><em>451 - 135 = 316 / 2 = 158
</em></u>
So your answer is 158.
"AB84"
egoroff_w [7]2 years ago
7 0
451-135=316
316/2=158
so the answer is 158 girls
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The diameter of circles is 4 cm. ​
krok68 [10]

Answer:

Step-by-step explanation:

C=pi d, here d=4 so

C=pi X 4

8 0
2 years ago
Kenny has the following data:
lys-0071 [83]

Answer:

7

Step-by-step explanation:

If range is 6 then the difference between highest and lowest is 6 so 1 + 6 = 7 so b is equal to 7.

7 0
3 years ago
What is the mode and mean for class A and the range and medium for class B????
melamori03 [73]
Hello!

First you have to list the data in both classes

Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
------------------------------------------------------------------------------------------------------
First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

The mode is 61

To find the mean you add all the numbers together and divide the sum by the amount of numbers added

41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069

Divide this by the amount of numbers added

1069 / 18 = 59.3888...

The mean is 59.3888

The mode is 61 and the mean is 59.39 for class A
------------------------------------------------------------------------------------------------------
We are going to find the range and median for class B

To find the range you subtract the smallest number from the largest on

The smallest number is 41
The largest number is 95

Subtract these

95 - 41 = 54

The range is 54

To find the median you list the numbers from least to greatest and look for the number in the middle

41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95

The number in the middle is 78

The range is 54 and the median is 78
------------------------------------------------------------------------------------------------------
Hope this helps!
6 0
3 years ago
Can someone help me on number one plz. Help me by explaining the steps ;D
harina [27]
0+1=1 
1-0=1
1x1=1
1/1=1
1 is in everything if this didnt help tell me
3 0
2 years ago
Read 2 more answers
The width of a rectangle is 3x – 3. Its perimeter is 10x + 6. Find the length of the rectangle.
maks197457 [2]

Step-by-step explanation:

The first possibility

2(width) + 2(length) = perimeter

2(3x-3) + 2(length) = 10x+6

6x - 6 + 2(length) = 10x+6

2(length) = 4x + 12

length = 2x + 6

The second possibility.

rondhesha chodado in The width of a rectangle is 3x – 3. Its perimeter is 10x + 6. Find the length of the rectangle.

So you have the perimeter, P, can be found by doing u+u+v+v.

Simplifying gives:

P=2u+2v.

You are given the width is (3x-3).  Choose this to be u or v but not both.

Perimeter is given a (10x+6).

Let's plug this in:

(10x+6)=2(3x-3)+2v

We are solving for v.

First step: Distribute where you can:

10x+6=6x-6+2v

Now we want to isolate v.

So we will need to subtract (6v-6) on both sides:

 (10x+6)=2v

- (6x -6)

----------------------

4x+12  =2v

The right hand side contains a factor of 2.

The left hand side does too since 4x+12 can be factored as 2(2x+6).

2(2x+6)=2v

This implies v is 2x+6.

Let's check our work.

We have two sides with measurement 2x+6:  (2x+6)+(2x+6)=4x+12

We have two sides with measurement 3x-3:   (3x-3)+(3x-3)=  6x-6

Let's add those sums to find the perimeter:                             10x+6

That is the intended 

3 0
2 years ago
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