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natima [27]
1 year ago
9

Which of the following would you rather carry around with you: 15000g of lithium or 15000g palladium?

Chemistry
1 answer:
guajiro [1.7K]1 year ago
6 0

15000g Lithium can be carried around with you.


Lithium is the lightest or is considered as the least dense metal with a density of 0.534 g/cm³ which is comparable to the density of a pine wood. More the amount of density, more amount of mass that particular element has. Density is the ratio of mass to volume, or it tells how much matter is packed in a given area. Palladium is a heavy metal with 12.02 g/cm³. Therefore, it has more density or more mass than lithium so it would definitely be difficult to carry around palladium than lithium. palladium has high mass to volume ratio than lithium.


Thus, with respect to palladium, Lithium being a light metal can be carried around easily. 


Learn more about Lithium:

brainly.com/question/9717121


#SPJ9

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Answer:

It's D

Explanation:

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2 years ago
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Answer:

limiting reactant

Explanation:

<em>The term that will be used to describe zinc in this case is </em><em>limiting reactant.</em>

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In this case, the zinc metal in the reaction is completely consumed, making the hydrochloric acid to be in excess. The zinc thus determines the amount of the products formed,

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3 years ago
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How do ecosystems respond to natural disasters such as fires and floods :

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2 years ago
A bottle of wine contains 9.81 grams of C2H5OH, dissolved in 87.5 grams of water. The final volume of the solution is 100.0 mL.
dimulka [17.4K]

Answer:

[EtOH] = 2.2M and Wt% EtOH = 10.1% (w/w)

Explanation:

1. Molarity = moles solute / Volume solution in Liters

=> moles solute = mass solute / formula weight of solute = 9.8g/46g·mol⁻¹ = 0.213mol EtOH

=> volume of solution (assuming density of final solution is 1.0g/ml) ...

volume solution =  9.81gEtOH + 87.5gH₂O = 97.31g solution x 1g/ml = 97.31ml = 0.09731 Liter solution

Concentration (Molarity) = moles/Liters = 0.213mol/0.09731L = 2.2M in EtOH

2. Weight Percent EtOH in solution (assuming density of final solution is 1.0g/ml)

From part 1 => [EtOH] = 2.2M in EtOH = 2.2moles EtOH/1.0L soln

= {(2.2mol)(46g/mol)]/1000g soln] x 100% = 10.1% (w/w) in EtOH.

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