383.5 grams is the mass of water should be added to 22.0 g of KCl to make a 5.50 % by mass solution.
Explanation:
Given that:
Solution to be prepared is 5.5 %
mass of KCl is 22 gram
mass of water required =?
5.5 % solution means that
5.5 grams in 100 ml or gram of water to make solution.
let the water required is 5.5 + x, so the equation will be
5.5 =
x 100
121+ 5.5x = 2200
5.5 x = 2200-121
x = 
x = 378 grams
The mass of water added to KCl to make it 5.5% percent solution is
5.5 +378
= 383.5 grams.
to make the solution of 5.5 percent of KCl weighing 22 grams.
<span>Because you've added coefficients to the molecules on the right side of the equation, the number of oxygen atoms has changed. ...Add a coefficient of 5 to the oxygen molecule on the left side of the equation. ...<span>C3H8 + 5O2 --> 4H2O + 3CO2.</span><span>The carbon, hydrogen, and oxygen atoms are balanced</span></span>
City B is at a higher temperature because as you go higher in altitude the boiling point of water becomes lower.
Answer:
74 litre
Explanation:
using ideal gas eqation PV=nRT
here P(pressure)=81.8 kPa =81.8×10^3 Pa
moles=2.5
temperature=273.15+18=291.15K
Gas constant R=8.314m^3-Pa/K-mol
now, V=nRT/P = 8.314×2.5×291.5/81.8×10^3 ≈74litre
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