ABC in which point E is between points A and B, point D is between points A and C, point F is between points B and C, segments A
E and EB are congruent, segments BF and FC are congruent, and angles AED, ABF, and DFC are right angles.Group of answer choices3 cm4 cm5 cm6 cm
1 answer:
Solution:
Given:
The meaning of circumscribed is drawing a figure around another figure in such a way that the drawn figure touches the outer line or points of the inside figure without intersecting it.
Hence, to circumscribe a cylinder about the candy bar, a circular path is drawn to touch the vertices of the points A, B, and C.
To circumscribe a circle around a triangle, the center of the circle is the point of intersection of the perpendicular bisectors of the sides of the triangle.
The point of intersection common to the bisectors is point D.
Hence, the circle is center D.
Given that AD = 2.5cm, then the radius of the circle = AD = 2.5cm
Hence, the diameter of the circle is;
Therefore, the diameter is 5cm
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Answer:
Option a) A 95% confidence interval for the mean diameter of the 120 bearings in the sample is .
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 120
Sample mean = 10 mm
Standard Deviation = 0.24 mm
Formula:
Hence, the correct interpretation for the confidence interval is given by option a).
A 95% confidence interval for the mean diameter of the 120 bearings in the sample is .
We have to consider the factor of sampling of 120 ball bearings from a population of 10,000 ball bearings.
Answer:
>> Null hypothesis; H0: μ1 - μ2 ≥ 0
Null hypothesis; Ha: μ1 - μ2 < 0
>> z = 1.85
>> p-value = 0.03
>> there is evidence sufficient to reject the claim that average weekly food expenditure of households in City 1 is more than that of households in City 2.
The economist claim is not supported by data.
Step-by-step explanation:
We are given;
Sample mean of city 1; x1¯ = 164
Sample mean of city 2; x2¯ = 159
Sample size of city 1; n1 = 35
Sample size of city 2; n2 = 30
Standard deviation of city 1; σ1 = 12.5
Standard deviation of city 2; σ2 = 9.25
Let's define the hypotheses;
Null hypothesis; H0: μ1 - μ2 ≥ 0
Null hypothesis; Ha: μ1 - μ2 < 0
Test statistic which is the z-score Formula between 2 mean is;
z = ((x1¯ - x2¯) - 0)/√((σ1)²/n1) + ((σ2)²/n2))
z = (164 - 159 - 0)/√((12.5²/35) + (9.25²/30))
z = 5/2.705
z = 1.85
From online p-value from z-score calculator attached, using z = 1.85, one tailed, significance value of 0.05, we have;
p-value = 0.03
The p-value is less than the significance value, and so we will reject the null hypothesis and conclude that there is evidence sufficient to reject the claim that average weekly food expenditure of households in City 1 is more than that of households in City 2.
