ABC in which point E is between points A and B, point D is between points A and C, point F is between points B and C, segments A
E and EB are congruent, segments BF and FC are congruent, and angles AED, ABF, and DFC are right angles.Group of answer choices3 cm4 cm5 cm6 cm
1 answer:
Solution:
Given:
The meaning of circumscribed is drawing a figure around another figure in such a way that the drawn figure touches the outer line or points of the inside figure without intersecting it.
Hence, to circumscribe a cylinder about the candy bar, a circular path is drawn to touch the vertices of the points A, B, and C.
To circumscribe a circle around a triangle, the center of the circle is the point of intersection of the perpendicular bisectors of the sides of the triangle.
The point of intersection common to the bisectors is point D.
Hence, the circle is center D.
Given that AD = 2.5cm, then the radius of the circle = AD = 2.5cm
Hence, the diameter of the circle is;
Therefore, the diameter is 5cm
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(a) Take the Laplace transform of both sides:
where the transform of comes from
This yields the linear ODE,
Divides both sides by :
Find the integrating factor:
Multiply both sides of the ODE by :
The left side condenses into the derivative of a product:
Integrate both sides and solve for :
(b) Taking the inverse transform of both sides gives
I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that is one solution to the original ODE.
Substitute these into the ODE to see everything checks out: