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7 months ago

Fill in the table using this function rule. y=3x+5

Mathematics

1 answer:

Mademuasel [1]7 months ago

5 0

The complete table of values of the equation y = 3x + 5 is

x = -2, -1, 0, 1 2

y = -1 2 5 8 11

<h3>How to complete the table of values?</h3>

The complete question is added at the end of this solution

From the question, we have the following equation that can be used in our computation:

y = 3x + 5

From the table of values added at the end of this question, we have the following x values

x = -2, -1, 0, 1 and 2

Substitute x = -2, -1, 0, 1 and 2 in y = 3x + 5

So, we have the following representation

y = 3(-2) + 5 = -1

y = 3(-1) + 5 = 2

y = 3(0) + 5 = 5

y = 3(1) + 5 = 8

y = 3(2) + 5 = 11

So, the complete table of values is

x = -2, -1, 0, 1 2

y = -1 2 5 8 11

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The mean amount of water in 5 containers is 620 ml the total amount of water in 4 q of the containers is 2750 what is the amount

EleoNora [17]

The correct answer is:

350 ml.

Explanation:

Let x be the amount in the fifth container.

The mean is found by adding all of the amounts together and dividing by the number of containers (in this problem, 5). We know that the total from the other 4 containers is 2750; add this to x, our unknown number. Then we divide by 5 to arrive at our answer of 620.

Algebraically,
 $\frac{2750+x}{5}=620$ 

To solve, multiply both sides by 5:
 $\frac{2750+x}{5}\times 5=620\times 5
\\
\\2750+x=3100$ 

Subtract 2750 from both sides:
2750+x-2750=3100-2750
x=350.

There are 350 ml in the fifth container.

6 0

2 years ago

Read 2 more answers

A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

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AVprozaik [17]

Answer:

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3 years ago

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Tpy6a [65]

Answer:

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Step-by-step explanation:

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using pythagorean theorem on triangle ABC gets the hypotenuse length of 39 which can be applied to FE

add all the values together

39 + 13 + 15 + 36 +12 +5 = 120

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oksano4ka [1.4K]

Yes it is true:

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2 years ago