An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:1. If the diameter of the cone is 2 inches and the height is 6 inches, what is the volume of vanilla ice cream in the cone? (round to nearest tenth)
2 answers:
<span>An ice cream cone is filled with vanilla and chocolate ice cream at a ratio of 2:1. If the diameter of the cone is 2 inches and the height is 6 inches, what is the volume of vanilla ice cream in the cone? (round to nearest tenth) ---- Total volume = pi*r^2*h = pi*1^2*6 = 6pi in^2 --------------------- Equation: 2x + x = 6pi 3x = 6pi x = 2pi (chocolate volume) 2x = 4pi (vanilla volume) </span>
Volume of cone=(1/3)hpir^2 d/2=r d=2 d/2=2/2=1=r h=6 V=(1/3)6pi1^2 V=2pi in^3 is volume ratio of 2:1 2+1=3 2pi=3 units divide both sides by 3 2/3pi=1 unit vanila=2 units times 2/3pi by 2 4/3pi aprox pi=3.141592 4.188 round 4.2 in^3 of vanilla
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Answer:
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48pi or ~150.8
Step-by-step explanation:
ok so area = pi * r^2
r = 8
8^2 = 64pi
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16*3 quarters shaded = 48
48pi is the answer
48pi or ~150.8