Hello! The answer should be B: 6i
![\sqrt{6](https://tex.z-dn.net/?f=%20%5Csqrt%7B6)
. Since the square root is above a negative, an imaginary number would come out. Because of this, you can easily recognize that it would be B.
However, if you can't, you could use the calculator to check (ignoring the negatives), 6
![\sqrt{6](https://tex.z-dn.net/?f=%20%5Csqrt%7B6)
is equal to
![\sqrt{216}](https://tex.z-dn.net/?f=%20%5Csqrt%7B216%7D%20)
.
The final answer should be B.
Answer:
6.4 kilometer
==============================
Step-by-step explanation:
See the attached figure.
Let Julian starts from point O (0,0)
Julian jogs 2 kilometers east ⇒ arrived to point A (2,0)
4 kilometers north ⇒ arrived to point B (2,4)
and then 7 kilometers west ⇒ arrived to point C (-5,4)
How far is Julian from his starting position?
So, it is required to find the distance OC
From the graph OC = ![\sqrt{(-5)^2+(4)^2}=\sqrt{25+16} =\sqrt{41} =6.403](https://tex.z-dn.net/?f=%5Csqrt%7B%28-5%29%5E2%2B%284%29%5E2%7D%3D%5Csqrt%7B25%2B16%7D%20%20%3D%5Csqrt%7B41%7D%20%3D6.403)
So, the distance from his starting position ≈ 6.4 km (to the nearest tenth of a kilometer)
Given:
The expression is 410 − 33.66.
To find:
The value of expression with the appropriate number of decimal places.
Solution:
We have,
![410 -33.66](https://tex.z-dn.net/?f=410%20-33.66)
It can be written as
![410 - 33.66=410-(33+0.66)](https://tex.z-dn.net/?f=410%20-%2033.66%3D410-%2833%2B0.66%29)
![410 -33.66=410-33-0.66](https://tex.z-dn.net/?f=410%20-33.66%3D410-33-0.66)
![410 - 33.66=377-0.66](https://tex.z-dn.net/?f=410%20-%2033.66%3D377-0.66)
Now,
![410 -33.66=376+(1-0.66)](https://tex.z-dn.net/?f=410%20-33.66%3D376%2B%281-0.66%29)
![410 -33.66=376+(0.34)](https://tex.z-dn.net/?f=410%20-33.66%3D376%2B%280.34%29)
![410 -33.66=376.34](https://tex.z-dn.net/?f=410%20-33.66%3D376.34)
Therefore, the required value is 376.34.
Answer:
Step-by-step explanation:
(2005, 12,000) (2005, 12,000)
x1 y1 x2 y2
m= (12,250-1200) / (2010-2005) = 250/5 = 50/1 = or 50
Answer:
DIVISION PROPERTY OF EQUALITY
Step-by-step explanation:
Given the equation r4 = 16,wm we can rewrite the equation as 4r = 16
The coefficient at the left hand side of the equation that we are to move to rge right is 4 (the number attached to the r variable). To do this we are going to apply the Division property of equality. This property is a property where both sides of an equation is divided through by the same constant without affecting the equality sign or by still keeping the equation.
To move the coefficient of r to the other side, we will divide both sides of the equation by 4 as shown;
4r/4 = 16/4
r = 4×4/4
r = 4
Hence the property that is used to move the coefficient (4) to the other side of the equation is the DIVISION PROPERTY OF EQUALITY.