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kobusy [5.1K]
3 years ago
11

Eli and Angela are saving money to buy their grandparents an anniversary gift. Eli has saved 8 more than 1/3 of Angela's savings

. If they each save $10 more. Eli will have saved S4 more than Angela's savings. How much has Eli saved?
Mathematics
1 answer:
Trava [24]3 years ago
4 0

Answer:

$10

Step-by-step explanation:

Let a = the amount Angela has saved.

Let e = the amount Eli has saved.

"Eli has saved $8 more than 1/3 of Angela's savings."

e = a/3 + 8

"If they each save $10 more." then

Eli will have: e + 10

Angela will have a + 10

"Eli will have saved $4 more than Angela's savings."

e + 10 = a + 10 + 4

This equation simplifies to: e = a + 4

We have a system of two equations in two variables.

e = a/3 + 8

e = a + 4

Since both equations are solved for e, we just equate the right sides.

a/3 + 8 = a + 4

Subtract a/3 from both sides. Subtract 4 from both sides.

a/3 - a/3 + 8 - 4 = a - a/3 + 4 - 4

4 = (2/3)a

Multiply both sides by 3/2

(3/2)4 = (3/2)(2/3)a

6 = a

a = 6

Angela has $6.

e = a + 4 = 6 + 4 = 10

Eli has $10.

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myrzilka [38]
<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

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