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drek231 [11]
1 year ago
14

Please help me fast. Trying to figure this out. Answer a-C. You don’t need to explain

Mathematics
1 answer:
dlinn [17]1 year ago
7 0

Answer:

The value of b would be $25 since it's the initial amt. The value of m would be $8. The equation would be y=8x+25

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What is the area of the shaded region?
kotegsom [21]

Answer:

Step-by-step explanation:

(7*11)-(22/7*2^2)

77-(22/7*4)

77-88/7

77-12.57

64.43

3 0
2 years ago
There are 3 3/4 cookies. if there is 1/4 of a cookie in each bag, how many bags are there?
Svetlanka [38]

Answer:

15 bags

Step-by-step explanation:

3 = 12/4

3 3/4 = 3+3/4 = 12/4 + 3/4 = (12+3)/4 = 15/4

(15/4) ÷ (1/4) = 15

5 0
2 years ago
Find the product. x3(x2+5x+1)
PtichkaEL [24]

Answer:

Answer = x5+5x4+x3

Step-by-step explanation:

x3(x2+5x+1)

=(x3)(x2+5x+1)

=(x3)(x2)+(x3)(5x)+(x3)(1)

=x5+5x4+x3

Answer = x5+5x4+x3

7 0
3 years ago
The temperature has been dropping 2 1/2 degrees every hour and the current temperature is -15°f. How many hours ago was it 0°f?
beks73 [17]

Answer:

6 hours ago

Step-by-step explanation:

6 hrs x 2.5 degrees = 15 degrees

5 0
2 years ago
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938


Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
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