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Nataly [62]
1 year ago
5

Graph (-6,32/3) on a number line

Mathematics
1 answer:
e-lub [12.9K]1 year ago
8 0

Given the point (-6, 32/3)

x-coordinates = -6

y-coordinates = 32/3 = 10 2/3

The graph of the point will be as follows:

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You go for a run on monday you run 2.41Km on tuesday you ran the same distance how far did you ran altogether
FrozenT [24]

Answer: 4.82 km

Step-by-step explanation:

You went for a run on Monday.

You then went on a run on Tuesday as well. On this day you ran 2.41 km and it is said that you ran the same distance on both days which means you ran for 2.41 km on Monday as well.

The total distance you ran is therefore:

= 2.41 + 2.41

= 4.82 km

4 0
3 years ago
One year, in school A, 162 students leave and 109 go to university. In school B, 75 students leave and 68 go to university. Comp
eduard

Answer:

in school a , 67.3 % of leaving students go to university.

in school b ,90.7% of leaving students go to university

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Two integers, a and b, have a greatest common factor of 1. If a =12 and b is greater than 35 but no more than 40, what is the va
yarga [219]

Answer: 37

Step-by-step explanation:

a=12

35 < b < 40

\wedge\ means\ GCF\\a\ \wedge\ b= 1\\12\ \wedge\ 37= 1\\12\ \wedge\ 38= 2\\12\ \wedge\ 39= 3\\

7 0
3 years ago
Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin
Allisa [31]

There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0
3 years ago
The Columbia Tower in Seattle is 954 feet tall. The Seafirst Tower is T feet tall and d feet away from the Colombia Tower. Find
Blababa [14]
You have to include a drawing that relates the distace between de towers and some angles.

I will use one that gives the angle from the base of Seafirst Tower to the top of Columbia tower as 53 degress.

This lets you calculate the distance between the towers, d, as

tan(53) = 954 / d => d = 954 / tan(53) = 718.89ft

The same drawing gives the angle from the the base of the Columbtia tower to the top of the Seafirst Tower as 27 degrees.

Tnen, tan(27) = height / d => height = d*tan(27) = 718.89*tan(27) = 366.29 ft

Answer: 366.29 ft


6 0
3 years ago
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