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Pie
1 year ago
15

What is the speed of a car which travels 45 miles in 3 hours?

Physics
2 answers:
Katen [24]1 year ago
6 0

Answer:

15 mph

Explanation:

45/3=15

zalisa [80]1 year ago
6 0

Answer:

45

Explanation:

do the math

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The height of the Washington Monument is measured to be 170.00 m on a day when the temperature is 35.0°C. What will its height b
N76 [4]

Answer:

169.98 m

Explanation:

\alpha = Thermal coefficient of marble = 2.5\times 10^{-6}/^{\circ}C

L_0 = Initial length = 170 m

\Delta T = Change in temperature = (-10-35)°C

Change in length is given by

\Delta L=\alpha L_0\Delta T\\\Rightarrow \Delta L=2.5\times 10^{-6}\times 170\times (-10-35)\\\Rightarrow \Delta L=-0.019125\ m

The height on the given day will be 170-0.019125=169.98\ m

3 0
4 years ago
What is the term for the matter through which a mechanical wave travels?
pav-90 [236]
The answer is “ The medium”
7 0
3 years ago
A tennis player practices against a wall, hitting a 0.1 kg ball towards the
pantera1 [17]

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

3 0
3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.383. At what minimum rate wo
djverab [1.8K]

Answer:

25.59 m/s²

Explanation:

Using the formula for  the force of static friction:

f_s = \mu_s N --- (1)

where;

f_s = static friction force

\mu_s = coefficient of static friction

N = normal force

Also, recall that:

F = mass × acceleration

Similarly, N = mg

here, due to min. acceleration of the car;

N = ma_{min}

From equation (1)

f_s = \mu_s ma_{min}

However, there is a need to balance the frictional force by using the force due to the car's acceleration between the quarter and the wall of the rocket.

Thus,

F = f_s

mg = \mu_s ma_{min}

a_{min} = \dfrac{mg }{ \mu_s m}

a_{min} = \dfrac{g }{ \mu_s }

where;

\mu_s = 0.383 and g = 9.8 m/s²

a_{min} = \dfrac{9.8 \ m/s^2 }{0.383 }

\mathbf{a_{min}= 25.59 \ m/s^2}

3 0
3 years ago
A car accelerate uniformly from rest at 5m/s2 . Determine it's speed after 10s​
krek1111 [17]

Answer:

50m/s.

Explanation:

Let's take acceleration as A and speed as S:

A = 5m/s²

S = A × 10s = 5 × 10 = 50m/s

The answer is 50m/s.

6 0
4 years ago
Read 2 more answers
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