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ozzi
3 years ago
15

A solid sphere of radius r carries charge q distributed uniformly throughout its volume. find the potential difference from the

sphere's surface to its center.
Physics
1 answer:
erastova [34]3 years ago
8 0

Answer: The potential difference from the sphere's surface to its center is zero.

Explanation:

The expression for the potential difference due to charge is as follows;

\Delta V=\frac{q}{4\pi \epsilon _{0}r}

Here, \Delta V is the potential difference, q is the charge, r is the position and \epsilon _{0}} is the absolute permittivity of free space.

In the given problem, a solid sphere of radius r carries charge q distributed uniformly throughout its volume.

To find the potential difference from the sphere's surface to its center. Put r=0 in the expression of the potential difference.

\Delta V=\frac{q}{4\pi \epsilon _{0}(0)}

\Delta V=0

Therefore, the  potential difference from the sphere's surface to its center is zero.

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