Answer:
0.2 m/s^2
Explanation:
Maximum distance, h = 19.5 m
initial speed, u = 2.80 m/s
final speed, v = 0 m/s
Let the gravitational acceleration is a.
Use third equation of motion



a = 0.2 m/s^2
Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2
Answer:
Option C. The force between them would be 4 times larger than with the
initial masses.
Explanation:
To know which option is correct, we shall determine the force of attraction between the two masses when their masses are doubled. This can be obtained as follow:
From:
F = GMₐM₆/ r²
Keeping G/r² constant, we have
F₁ = MₐM₆
Let the initial mass of both objects to be m
F₁ = MₐM₆
F₁ = m × m
F₁ = m²
Next, let the masses of both objects doubles i.e 2m
F₂ = MₐM₆
F₂ = 2m × 2m
F₂ = 4m²
Compare the initial and final force
Initial force (F₁) = m²
Final (F₂) = 4m²
F₂ / F₁ = 4m² / m²
F₂ / F₁ = 4
F₂ = 4F₁ = 4m²
From the above illustrations, we can see that when the mass of both objects doubles, the force between them would be 4 times larger than with the
initial masses.
Thus, option C gives the correct answer to the question.
Answer:
m = 63.7 kg
Explanation:
As we know that when mass connected to the bungee cord stretch the string then the gravitational potential energy of the person will convert into potential energy of the string at the end
now here we know that when person jump from the top and reach at the end then loss in gravitational potential energy is given as



now when it is at the end of the motion stretch in the string will be

now potential energy of string is given as


now by energy conservation we have


c is what you want from a fire ?