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professor190 [17]
1 year ago
7

Billy plans to paint baskets. The paint costs $14.50. The baskets cost $7.25. Write an equation that gives the total cost as a f

unction of the number of baskets made. Determine the cost of 4 baskets
Mathematics
1 answer:
andreyandreev [35.5K]1 year ago
7 0

Let 'x' represent the number of baskets and let 'y' be the total cost.

Since the paint costs 14.50 and each basket cost 7.25, then we have the following function:

y=7.25x+14.50

To find the cost of 4 baskets, we can make x = 4 and solve for y:

\begin{gathered} x=4 \\ \Rightarrow y=7.25(4)+14.50=29+14.50=43.50 \\ y=43.50 \end{gathered}

therefore, the cost of painting 4 baskets is $43.50

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Answer:

Step-by-step explanation:

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3 years ago
a store owner wishes to make a new tea with a unique flavor by mixing black tea and oolong tea. if he has 35 pounds of oolong te
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35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of black tea worth 1.80 per pound to be mixed to get the final mixture for 2.10 per pound, hence:

2.4(35) + 1.8(x) = 2.1(x + 35)

x = 35 pounds

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

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2 years ago
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8.2 x 10 ^-5 in standard notation
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3 years ago
Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3
chubhunter [2.5K]

Answer:

The simplified form is \dfrac{2(x-1)}{3(x+1)}.

x =1 is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

\dfrac{2a^2-4a+2}{3a^2-3}

Let us simplify the numerator and denominator separately.

The numerator is given as 2a^2-4a+2

2 is a common factor in all the three terms. So, we factor it out. This gives,

=2(a^2-2a+1)

Now, a^2-2a+1=(a-1)(a-1)

Therefore, the numerator becomes 2(a-1)(a-1)

The denominator is given as: 3a^2-3

Factoring out 3, we get

3(a^2-1)

Now, a^2-1 is of the form a^2-b^2=(a-b)(a+b)

So, a^2-1=(a-1)(a+1)

Therefore, the denominator becomes 3(a-1)(a+1)

Now, the given expression is simplified to:

\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}

There is (x-1) in the numerator and denominator. We can cancel them only if x\ne1 as for x=1, the given expression is undefined.

Now, cancelling the like terms considering x\ne1, we get:

\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}

Therefore, the simplified form is \dfrac{2(x-1)}{3(x+1)}

The simplification is true only if  x\ne1. So, x =1 is the excluded value for the given expression.

8 0
3 years ago
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