Answer : The concentration of copper(II) fluoride in the solution is, 
Explanation : Given,
Moles of copper(II) fluoride = 0.032 μ
mol = 
conversion used : 
Volume of solution = 500 mL
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :

Now put all the given values in this formula, we get:

Therefore, the concentration of copper(II) fluoride in the solution is, 
We assume that the given gas, NO2, is an ideal gas such that we will be able to use the equation,
n/V = P/RT
where n is the number of moles, V is volume, P is pressure, R is gas constant, and T is temperature in kelvin. Substituting the known values,
n/V = (1 atm) / (37 + 273)(0.0821 L.atm/mol.K)
n/V = 0.039 mol/L
Converting this to density by multiplying the value with the molar mass,
density = (0.039 mol/L) x (46 g/mol) = 1.8 g/L
This should be most likely true