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mylen [45]
3 years ago
12

How many grams are in 4.58x1023 atoms of oxygen?

Chemistry
1 answer:
zalisa [80]3 years ago
6 0
4685.34 atoms of oxygen
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How much heat (in Joules) is needed to raise the temperature of 257g of ethanol (cethanol=2.4 J/g°C) by 49.1°C?
Sonbull [250]

Answer:

Q = 30284.88 j

Explanation:

Given data:

Mass of ethanol = 257 g

Cp = 2.4 j/g.°C

Chnage in temperature = ΔT = 49.1°C

Heat required = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = 257 g× 2.4 j/g.°C × 49.1 °C

Q = 30284.88 j

8 0
3 years ago
Help PLEASE HELP PLEASE
Gennadij [26K]

Answer:

b. k+

Explanation:

4 0
3 years ago
when 48 .0g of carbon reacts with oxygen gas to form carbon dioxide, no carbon or oxygen is left over. How much oxygen is reacte
Arte-miy333 [17]

Answer:

128g

Explanation:

Given parameters:

Mass of carbon  = 48g

Mass of carbon dioxide  = 176g

Unknown:

Mass of oxygen that reacted  = ?

Solution:

Every chemical reaction must obey the law of conservation of mass. It states that "in a chemical reaction, matter is neither created nor destroyed" .

So;

     Mass of carbon + Mass of oxygen  = Mass of carbon dioxide

Mass of oxygen  = Mass of carbon dioxide  - Mass of carbon

Mass of oxygen  = 176  - 48  = 128g

3 0
2 years ago
In the synthesis reaction, the white powder produced is magnesium oxide (mgo, mm = 40.3 g/mol). how many moles of magnesium oxid
gulaghasi [49]
Number of moles = mass of product / molecular mass
=mass of product (MgO) / 40.3

Since the mass of MgO is not given in the question, the correct answer choice cannot be given.  However, proceeding witht eh above formula will enable you to find the correct number of moles given the mass of MgO.
3 0
3 years ago
The combustion of hydrogen and oxygen is commonly used to
posledela

Answer:

6.66 mol

Explanation:

(atm x L) ÷  (0.0821 x K)

(0.875 x 250) ÷  (0.0821 x 400)

=6.66108

5 0
2 years ago
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