Question

The cell potential of an electrochemical cell with the cell reaction 2al(s) + 3zn2+(aq) → 3zn(s) + 2al3+(aq) is 1. 607 v. What is the maximum electrical work obtainable from this cell when 0. 50 g of al is consumed?

Answer 1

The cell potential of an electrochemical cell with the cell reaction  is 1. 607 v.  the maximum electrical work obtainable from this cell when 0. 50 g of al is consumed is - 9.3 × 10⁵ J.

The reaction is given as :

2Al  +  3Zn²⁺  ---->   3Zn   +   2Al³⁺

the maximum electrical work obtainable from this cell:

ΔG = - n FE°cell

where,

maximum electrical work = ΔG

n = no. of transfer electron = 2 × 3 = 6 e⁻

E°cell = 1.607 V

ΔG = - n FE°cell

ΔG = - 6 × 9.65 × 10⁴ ×  1.607

ΔG = - 9.3 × 10⁵ J

Thus the maximum electrical work obtain from this cell is - 9.3 × 10⁵ J.

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