3 years ago

When 29 grams of sodium metal (Na) react with 49 grams of chlorine gas (C1), solid

Chemistry

1 answer:

Scrat [10]3 years ago

4 0

Answer:

Explanation:

Na + Cl = NaCl

23 g 35.5 g

23 g sodium reacts with 35.5 g of chlorine

29 g of sodium reacts with 35.5 x 29 / 23 g of chlorine

= 44.76 g

So 44.76 g of chlorine reacts and 49 - 44.76 = 4.24 g of chlorine is left over .

All the sodium is used up in the reaction .

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