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Anna [14]
3 years ago
11

When 29 grams of sodium metal (Na) react with 49 grams of chlorine gas (C1), solid

Chemistry
1 answer:
Scrat [10]3 years ago
4 0

Answer:

Explanation:

Na     +     Cl    =      NaCl

23 g        35.5 g  

23 g sodium reacts with 35.5 g of chlorine

29 g of sodium reacts with 35.5 x 29 / 23 g of chlorine

= 44.76 g

So 44.76 g of chlorine reacts and 49 - 44.76 = 4.24 g of chlorine is left over .

All the sodium is used up in the reaction .

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<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range  

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HNO₃ + NaOH → NaNO₃ + H₂O​

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moles NaOH=

\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

<em></em>

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