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Mariana [72]
1 year ago
5

I can send the other options? I just need this explained?

Mathematics
1 answer:
OLEGan [10]1 year ago
3 0

The standard equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

For:

\begin{gathered} (x+3)^2+(y+1)^2=16 \\  \end{gathered}

Rewrite the equation as:

\begin{gathered} (x-(-3))^2+(y-(-1))^2=4^2 \\ so\colon \\ h=-3 \\ k=-1 \\ r=4 \end{gathered}

We can conclude it is a circle with center at (-3,-1) and radius of 4

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Find the distance between the points (5, -3) and (0, 2).
ohaa [14]

Answer:

Distance between points  (5, -3) and (0, 2) is √50 or 7.07

Step-by-step explanation:

We need to find distance between two points (5,-3) and (0,2)

The distance formula used is:

d= \sqrt {\left( { x_2-x_1 } \right)^2 + \left( {y_2-y_1} \right)^2 }

here

x₁= 5, y₁=-3, x₂=0 and y₂=2

Putting values in the formula:

d= \sqrt {\left( {x_2-x_1} \right)^2 + \left( {y_2-y_1} \right)^2 }\\d= \sqrt {\left( {0-5} \right)^2 + \left( {2-(-3)} \right)^2 }\\d= \sqrt {\left( {-5} \right)^2 + \left( {2+3} \right)^2 }\\d= \sqrt {25+25}\\d= \sqrt {50}\\d= 7.07

So, distance between points  (5, -3) and (0, 2) is √50 or 7.07

7 0
3 years ago
Read 2 more answers
Which value is included in the solution set for the inequality graphed on the number line​
marissa [1.9K]

Answer:

-5

Step-by-step explanation:

On the number line, the arrow is from -2 (opens) to the left; that means solutions will be any values less than -2

So

-5 < -2 : YES ( solutions will be any values less than -2)

-2 = -2 : NO  (solutions will be any values less than -2)

0 > -2 : NO  (solutions will be any values less than -2)

3 > -2 : NO  (solutions will be any values less than -2)

Answer

- 5

3 0
3 years ago
Read 2 more answers
HELPPP Pleaseeee
Mariana [72]

Answer:

1,749

8,349

Step-by-step explanation:

We can multiply 6,600 by 1.265 to get 8,349. To get the percentage all we have to do is multiply 6,600 by .265 and get 1,749.

Hope this helps

3 0
2 years ago
What Properties or characteristics or similar triangles could be used to prove the Pythagorean theorem?
Zolol [24]
Well, in order to prove the Pythagorean theorem, every triangle you are using has to have one right angle (90-degree angle), and the side opposite to it will be called the hypothenuse. The remaining two triangles will be acute angles (<90 degrees), and the sides opposite to them are called sides/catheti. 
4 0
3 years ago
The midpoint of AB is at (3,7) and A is at (0,-5). Where is B located?
Veronika [31]
I attached your answer below...

4 0
3 years ago
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