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1 year ago

What is the total number of protons in an atom with the electron configuration 2-8-18-32-18-1.

1 answer:

5 0

The total number of protons in this atom is 79 because an atomic number of an element is equal to the number of protons. Here, the atomic number is 79 after adding the given electronic configuration.

What are Protons?

Every atom has a proton, a subatomic particle, in its nucleus. The particle possesses an electrical charge that is positive and opposite to the electrons.

What is Atom?

A nucleus plus one or more electrons bound to the nucleus make up an atom. The quantity of protons or electrons in an element's atom determines how different it is from other similar elements. The atomic number of an element, which serves as its primary identification, is the sum of its protons or electrons.

What is Electronic configuration?

The arrangement of electrons in atomic or molecular orbitals within an atom, molecule, or other physical structure is known as the electron configuration.

Hence, the total number of protons in this atom is 79, after adding 2 + 8 + 18 + 32 + 18 + 1.

To know more about Atom, check out:

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3 years ago

What occurs when Cr^3+ ions are reduced to Cr^2+ ions?

DiKsa [7]

D:

When electrons are gained, the charge of the atom decreases.

When you are given an atom with a charge, the oxidation of that atom is the charge. So by going from a Cr^3+ (Oxidation Number = 3) to a Cr^2+ (Oxidation Number = 2), the Oxidation Number thus decreases.

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3 years ago

A container initially holds 5.67 x 10^-2 mol of propane and has a volume of V1. The volume of the container was increased by add

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Answer:

Initial volume of the container (V1) = 1.27 L (Approx)

Explanation:

Given:

Number of mol (n1) = 5.67 x 10⁻²

Number of mol (n2) = (5.67 +2.95) x 10⁻² = 8.62 x 10⁻²

New volume (V2) = 1.93 L

Find:

Initial volume of the container (V1)

Computation:

Using Avogadro's law

V1 / n1 = V2 / n2

V1 / 5.67 x 10⁻² = 1.93 / 8.62 x 10⁻²

V1 = 10.9431 / 8.62

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3 years ago

The average atomic weight of copper, which has two naturally occurring isotopes, is 63.5. One of the isotopes has an atomic weig

Darya [45]

<u>Answer:</u> The atomic weight of the second isotope is 64.81 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of atomic masses of each isotope each multiplied by their natural fractional abundance

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

We are given:

Let the mass of isotope 2 be 'x'

Mass of isotope 1 = 62.9 amu

Percentage abundance of isotope 1 = 69.1 %

Fractional abundance of isotope 1 = 0.691

Mass of isotope 2 = 'x'

Percentage abundance of isotope 2 = 30.9%

Fractional abundance of isotope 2 = 0.309

Average atomic mass of copper = 63.5 amu

Putting values in equation 1, we get:

$\text{Average atomic mass of copper}=[(62.9\times 0.691)+(x\times 0.309)]$

$x=64.81amu$

Hence, the atomic weight of second isotope will be 64.81 amu.

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